Envers添加用户信息

Question

Envers有问题。起初，这里有我的两个Hibernate类：

child.java：

@Entity 
@Audited 
public class child { 
    @Id 
    private int id; 
    private String text; 
    @ManyToOne 
    @JoinColumn(name="child") 
    private testclass parent; 
    public int getId() {return id;} 
    public void setId(int id) {this.id = id;} 
    public String getText() {return text;} 
    public void setText(String text) {this.text = text;} 
    public testclass getParent() {return parent;} 
    public void setParent(testclass parent) {this.parent = parent;} 
} 

testclass.java：

@Entity 
@Audited 
public class testclass { 
    @Id 
    @GeneratedValue(strategy=GenerationType.SEQUENCE, generator="seq_template") 
    @SequenceGenerator(name="seq_template", sequenceName="tester_seq") 
    private int id; 

    private String text; 

    @OneToMany(mappedBy="parent") 
    private Set<child> childs; 

    public int getId() {return id;} 
    public void setId(int id) {this.id = id;} 
    public String getText() {return text;} 
    public void setText(String text) {this.text = text;} 
    public Set<child> getChilds() {return childs;} 
    public void setChilds(Set<child> childs) {this.childs = childs;} 
} 

两个类都做工精细和审计信息，如时间戳存储好。

我想现在用审计信息用户名来扩展信息。为此，我创建了这些配置文件：

<?xml version="1.0" encoding="UTF-8"?> 
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd"> 
<hibernate-mapping package="ch.triwdata.envers.extensions"> 
    <class name="ExtendedRevisionEntity" table="revinfo"> 
     <id name="id" type="int"> 
      <column name="rev" not-null="true"/> 
      <generator class="native"/> 
     </id> 
     <property name="timestamp" type="long" column="timestamp" /> 
     <property name="username" type="string" not-null="true"/> 
    </class> 
</hibernate-mapping> 

有当然也与休眠配置的配置文件，但我不认为这是很重要的位置。

有人可以看到我的失败，为什么用户信息不存储？

问候 比约恩

PS： 也许这XML缺什么？自从开始，我添加了它：

<?xml version="1.0" encoding="UTF-8"?> 
<!DOCTYPE hibernate-configuration PUBLIC "-//Hibernate/Hibernate Configuration DTD 3.0//EN" "http://www.hibernate.org/dtd/hibernate-configuration-3.0.dtd"> 
<hibernate-configuration> 
    <session-factory> 
     <property name="hibernate.connection.url">jdbc:postgresql://localhost/postgres</property> 
     <property name="hibernate.connection.username">user</property> 
     <property name="hibernate.connection.driver_class">org.postgresql.Driver</property> 
     <property name="connection.password">****</property> 
     <property name="connection.pool_size">1</property> 
     <property name="hibernate.dialect">org.hibernate.dialect.PostgreSQLDialect</property> 
     <property name="show_sql">true</property> 
     <property name="hbm2ddl.auto">create-drop</property> 

     <mapping class="testclass"/> 
     <mapping class="child"/> 
    </session-factory> 
</hibernate-configuration> 

Answer 1

我明白了！ ：d

的失败是在这里：

<?xml version="1.0" encoding="UTF-8"?> 
<!DOCTYPE hibernate-configuration PUBLIC "-//Hibernate/Hibernate Configuration DTD 3.0//EN" "http://www.hibernate.org/dtd/hibernate-configuration-3.0.dtd"> 
<hibernate-configuration> 
    <session-factory> 
     <property name="hibernate.connection.url">jdbc:postgresql://localhost/postgres</property> 
     <property name="hibernate.connection.username">twd_genmeta</property> 
<!--   <property name="hibernate.connection.driver_class">com.p6spy.engine.spy.P6SpyDriver</property> --> 
     <property name="hibernate.connection.driver_class">org.postgresql.Driver</property> 
     <property name="connection.password">Deliaa</property> 
     <property name="connection.pool_size">1</property> 
     <property name="hibernate.dialect">org.hibernate.dialect.PostgreSQLDialect</property> 
     <property name="show_sql">true</property> 
     <property name="hbm2ddl.auto">create-drop</property> 

     <mapping class="ch.triwdata.envers.classes.testclass"/> 
     <mapping class="ch.triwdata.envers.classes.child"/> 
     <mapping resource="hibernate.hbm.xml"/> <---- this entry is missing 
    </session-factory> 
</hibernate-configuration> 

非常感谢您的回复！

问候 比约恩