2016-01-20 69 views
0

我正在尝试使用dataweave以特定格式创建json。Dataweave XML to JSON根据xml中的属性创建密钥对值

xml在某些元素中有属性,我需要用它来在json文件中创建一个未定义的键。

XML

<Ingredients> 
<Ingredient>225g/8oz unsalted butter, softened, plus extra for greasing</Ingredient> 
<Ingredient>175g/6oz dried cranberries</Ingredient> 
</Ingredients> 
<Ingredients Section="FOR THE FRUIT"> 
<Ingredient>150ml/¼pt cloudy apple juice</Ingredient> 
<Ingredient>50g/2oz unsalted butter</Ingredient> 
</Ingredients> 
<Ingredients Section="TO FEED THE CAKE (each time)"> 
<Ingredient>2 tbsp dark rum</Ingredient> 
<Ingredient>1 tbsp maple syrup</Ingredient> 
</Ingredients> 

JSON的输出应该是这样的。诀窍是当Section = null时,应该使用Ungrouped,否则使用Section的值。

JSON

{ 
    "ingredients": { 
     "Ungrouped": { 
      "position": 0, 
      "list": [{ 
       "position": 1, 
       "description": "225g/8oz unsalted butter, softened, plus extra for greasing" 
      }, { 
       "position": 2, 
       "description": "225g/8oz light muscovado sugar" 
      }] 
     }, 
     "FOR THE FRUIT": { 
      "position": 1, 
      "list": [{ 
       "position": 1, 
       "description": "150ml/¼pt cloudy apple juice" 
      }, { 
       "position": 2, 
       "description": "50g/2oz unsalted butter" 
      }] 
     }, 
     "TO FEED THE CAKE (each time)":{ 
      "position":2, 
      "list": [{ 
       "position": 1, 
       "description": "2 tbsp dark rum" 
      }, 
      { 
       "position": 2, 
       "description": "1 tbsp maple syrup" 
      }] 
     } 
    } 
} 

这里是我的数据编织的开始。我还没有取得进一步的进展,因为我能够设置未分组部分至关重要。

Dataweave

%dw 1.0 
%input payload application/xml 
%output application/json 
--- 
{ 
recipe: { 
"ingredients": { (payload.Recipe.*[email protected] map 
'Ungrouped':{ 
    position : $$+0 
    } when $ == null otherwise 

'$':{ 
    position : $$+0 
    } 
)} 
} 
} 

我希望我已经涵盖了一切。请让我知道,如果我没有,因为这是我在stackoverflow上的第一篇文章。

+0

所以,困难的部分是把所有具有无节,右边的成分?你可以有更多的配料标签没有部分? – Shoki

回答

0

如果没有其他Ingredients没有Section,那么你可以做:

%dw 1.0 
%output application/json 
%var addPosition = (list) -> list map { 
    "position": $$+1, 
    "description" : $ 
} 
--- 
recipe: ingredients: {(
    ("Ungrouped" + payload.Recipe.*[email protected]) map { 
    "$" : { 
     "position": $$, 
     "list": addPosition(payload.Recipe.*Ingredients[$$].*Ingredient) 
    } 
    } 
)} 
+0

真的很好的简单解决方案,我更多地了解了数据编织的功能。谢谢Shoki – Karim