2016-01-13 102 views
1

我用opener.open方法得到了json数据。现在我想参考它的elmentS。我尝试了下面的代码,但我得到错误!此外,我想仅为链接2获取token =的值。任何人都可以帮助我解决这个错误并获得令牌的价值吗?提前致谢。如何使用python解析json元素?

代码:

resp2 = opener.open('http://somewebsite.com/test/id',post_data) 
     print resp2.read() 
     Response = resp2.read(); 
     j_obj = json.load(Response) 
     print j_obj['link2'] 

错误:

ERROR: EXCEPTION Thrown (PythonToCppException) : 
-->Python callback/script returned the following error<-- 
- NOTE: IGNORING THIS CAN LEAD TO MEMORY LEAKS! 
Error Type: <type 'exceptions.AttributeError'> 
Error Contents: 'str' object has no attribute 'read' 
j_obj = json.load(Response) 
line 286, in load 
return loads(fp.read(), 
AttributeError: 'str' object has no attribute 'read' 
-->End of Python script error report<-- 

JSON数据:

{ 
     "id": 1, 
     "name": "Test World", 
     "link1": "rtmp:\/\/me.someWebsite.com:1234\/static\/testWorld1?token=123456789abcdefghijklmnopqr&e=987654321&u=99999", 
     "link2": "http:\/\/me.someWebsite.com:1234\/testWorld1\/index.m3u8?token=123456789abcdefghijklmnopqr&e=987654321&u=99999&channel=testWorld1", 
     "image": "http:\/\/me.someWebsite.com\/img\/1\/2\/3\/4\/56.png", 
     "net": "rtmp:\/\/me.someWebSite.com:1234\/static", 
     "url": "testWorld1?token=123456789abcdefghijklmnopqr&e=987654321&u=99999", 
     "favorite": false, 
     "date": "2014-05-1" 
    } 
+1

'json.load()'是文件类型的对象,'json.loads()'是用于字符串。 – AChampion

回答

2

执行以下操作 - 注意resp2已经是一个string

resp2 = opener.open('http://somewebsite.com/test/id',post_data) 
print resp2 # You can verify you are receiving JSON data here. 
j_obj = json.loads(resp2) 
print j_obj['link2'] 
+0

感谢您的回复。我现在尝试它现在我得到这个错误:错误类型:错误内容:没有JSON对象可以被解码Traceback(最近呼叫最后): – user1788736

+0

打印您收到的字符串。发布它包含的内容。 –

+0

非常感谢我删除了Response = resp2.read();并使用resp2现在我得到了link2的值。我怎么能得到该链接2上的标记的值?(标记= 123456789abcdefghijklmnopqr) – user1788736

1

你可以尝试使用不同的方法,

import urllib2 

    post_data = ... 
    fp = urllib2.urlopen('http://somewebsite.com/test/id', post_data) 
    resp = fp.read() 
    print(resp)