2015-05-29 130 views
0

我想获取从sever.when我查询JSON细节,它不是working.when我硬编码工作的网址..Retrofit查询无法正常工作?

CASE 1

@GET("/quiz/create_json/sub_cat.php?main_cat_id=") 
void showSubCategory1(@Query("id") int id,Callback<Object> callback); 

    retrofitService.showSubCategory1(id, new Callback<Object>() { 
     @Override 
     public void failure(RetrofitError error) { 

      Log.d(TAG, "Failure"); 

     } 

     @Override 
     public void success(Object list, Response response) { 
      Log.d(TAG, "Success "); 
      Log.d(TAG, "arraystting" + list.toString()); 

     } 
    }); 

其捐赠空数组..

CASE 2

@GET("/quiz/create_json/sub_cat.php?main_cat_id=1") 
void showSubCategory2(Callback<Object> callback); 

retrofitService.showSubCategory2(new Callback<Object>() { 
     @Override 
     public void success(Object o, Response response) { 
      Log.d(TAG, "Success "+o.toString()); 
     } 

     @Override 
     public void failure(RetrofitError error) { 
      Log.d(TAG, "Failure"); 

     } 
    }); 

这里给它适当的json。问题应该修复严重吗?

回答

2

我认为你应该这样指定它。

@GET("/quiz/create_json/sub_cat.php") 
void showSubCategory1(@Query("main_cat_id") int id, Callback<Object> callback); 
+0

在Retrofit2中,它会是'@GET(“quiz/create_json/sub_cat.php”)' – EpicPandaForce