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我有这个家庭作业问题。如何将序列存储在MIPS中的数组中?
编写一个产生以下序列的程序; 1,2,2,4,8,32,256,...并将其存储在一个数组中,具体取决于用户选择的术语数量。序列中的每个元素可以通过乘以它之前的两个元素来计算。换句话说,通过公式Sn = Sn-1×Sn-2来计算第n个序列号Sn。
我试过,但它并没有跑
我的代码
^^
# UNTITLED PROGRAM
.data # Data declaration section
str1: .ascii "Please enter the number of terms to produce: "
arr: .space 40
.text
main: # Start of code section
li $v0, 4 # system call code for printing string = 4
la $a0, str1 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 5 # get ready to read in integers
syscall # system waits for input
move $s0,$v0 # store the result of the read (returned in $v0) in num1
la $s1,arr
addi $t2,$zero,2 # i=2
addi $t0,$zero,1
add $t1,$t0,$t0
sw $t0,0($s1)
sw $t1,0($s1)
L1:
addi $t2,$t2,1 #i++
addi $s1,$s1,4
lw $t4,0($s1) #A[i-1]
lw $t5,4($s1)
mul $t3,$t4,$t5
sw $t3,8($s1)
beq $t2,$s0,print
j L1
print:
lw $t3,0($s1)
li $v0, 1 # system call code for print_int
move $a0, $t3 # integer to print
syscall # print it
addi $s1,$s1,4
beq $t2,$s0,Exit
j print
Exit:
li $v0, 10 # exits program
syscall
# END OF PROGRAM
你做了什么调试工作?你认为问题在哪里? – 2012-04-15 22:35:48
请格式化您的代码。 – blackcompe 2012-04-15 22:36:55
@MichaelPetrotta我用栈来保存结果然后在数组中排序..但是我的代码没有运行..最后,编码程序__ for循环=> A [i] = A [i-1] * A [i -2] 我认为问题如何从数组中加载字和排序字指令 – Dalal 2012-04-15 23:10:42