我正在通过编辑模板在我的网站上工作,但有一个下拉菜单不起作用。 CSS下拉菜单丢失。 如何使用CSS和/或JS修复它? 下面是HTML代码:与JS下拉菜单
<a href="#" id="ddnmenu">Bentornato {$mybb->user['username']}! <i class="fa fa-caret-down"></i></a>
<div id="ddnmenu_popup" class="popup_menu" style="display: none;">
<div class="popup_item_container">
<a href="{$mybb->settings['bburl']}/usercp.php" class="popup_item">User Panel<i class="fa fa-user menuadj"></i></a>
</div>
<div class="popup_item_container">
<a href="{$mybb->settings['bburl']}/usercp.php?action=profile" class="popup_item">Edit Profile<i class="fa fa-pencil menuadj"></i></a>
</div>
<div class="popup_item_container">
<a href="{$mybb->settings['bburl']}/usercp.php?action=options" class="popup_item">Edit Options<i class="fa fa-cogs menuadj"></i></a>
</div>
<div class="popup_item_container">
<a href="{$mybb->settings['bburl']}/usercp.php?action=avatar" class="popup_item">Edit Avatar<i class="fa fa-picture-o menuadj"></i></a>
</div>
<div class="popup_item_container">
<a href="{$mybb->settings['bburl']}/usercp.php?action=editsig" class="popup_item" style="padding-bottom: 4px;">Edit Signature<i class="fa fa-paint-brush menuadj"></i></a>
</div>
<div class="popup_item_container">
<a href="{$mybb->settings['bburl']}/member.php?action=logout&logoutkey={$mybb->user['logoutkey']}" class="popup_item">{$lang->welcome_logout}!<i class="fa fa-power-off menuadj"></i>
</a>
</div>
</div>
编辑: 我用你建议的解决方案,我用jQuery的,但是现在有一个问题...
菜单打开侧面按钮下方移动它,从而破坏整个菜单..
我该如何解决?
设置'''风格= “显示:块”'''第一 – syarul
@syarul好了,但现在它总是可见 – Takabrycheri