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我正在构建一个简单的tkinter密码程序,并且遇到问题。我收到以下错误信息:使用for循环将值插入到tkinter输入字段
Exception in Tkinter callback
Traceback (most recent call last):
File "/usr/lib/python3.4/tkinter/__init__.py", line 1536, in __call__
return self.func(*args)
File "password.py", line 23, in pass_gen
PassField.insert(0, random.choice(string.digits + string.ascii_letters), end='')
TypeError: insert() got an unexpected keyword argument 'end'
如果我删除末=“”错误消息就会消失,但如预期的代码不起作用。我最终得到一个数字密码而不是所需的长度。
import random
import string
from tkinter import *
from tkinter import ttk
root = Tk()
strength = IntVar()
length = DoubleVar()
root.title('Password Generator')
def pass_gen(event):
lengthy = int(PassLength.get())
print(lengthy)
if strength.get() == 1:
for i in range(0, lengthy):
PassField.delete(0, 'end')
PassField.insert(0, random.choice(string.ascii_letters), end='')
elif strength.get() == 2:
for i in range(0, lengthy):
PassField.delete(0, 'end')
PassField.insert(0, random.choice(string.digits + string.ascii_letters), end='')
elif strength == 'x':
for i in range(0, lengthy):
PassField.delete(0, 'end')
PassField.insert(0, random.choice(string.punctuation + string.digits + string.ascii_letters), end='')
Radiobutton(root, text="Weak", variable=strength, value=1).grid(row=0, column=0, sticky=N)
Radiobutton(root, text="Strong", variable=strength, value=2).grid(row=0, column=1, sticky=N)
Radiobutton(root, text="Extra-strong", variable=strength, value=3).grid(row=0, column=2, sticky=N)
Label(root, text='Length').grid(row=1, column=0, sticky=W, padx=4)
PassLength = Scale(root, variable=length, from_=0, to=30, orient=HORIZONTAL)
PassLength.grid(row=1, column=1)
Label(root, text='Password').grid(row=2, sticky=W, padx=4)
PassField = Entry(root)
PassField.grid(row=2, column=1, sticky=E, pady=4)
generateButton = Button(root, text='Generate')
generateButton.bind("<Button-1>", pass_gen)
generateButton.grid(row=2, column=2,sticky=E)
root.mainloop()
我很感激您的意见。 TIA
你期待什么'结束=“”'做什么?此外,您每次都通过循环显式删除内容。你为什么这样做? –
经过一番尝试,我知道我的问题是什么。不知道如何解决它。我正在使用end =''希望它将密码中的单个字符连接到选定的长度。 –