用PHP下载服务器上的几个文件的内容

Question

我有2个文件 - 1.csv and 2.csv。我可以通过已知的方法下载1.csv用PHP：

$file = '1.csv'; 
header('Content-Description: File Transfer'); 
header('Content-Type: application/jpeg'); 
header('Content-Disposition: attachment; filename='.basename($file)); 
header('Content-Transfer-Encoding: binary'); 
header('Expires: 0'); 
header('Cache-Control: public'); 
header('Pragma: public'); 
header('Content-Length: ' . filesize($file)); 
ob_clean(); 
flush(); 
readfile($file); 

但我的目的是要在这两个文件的下载的文件内容 - 1.csv和2.csv。有没有人有一些想法如何实现这一点？ 预先感谢您。

Answer 1

串联如果我理解正确，你这个应该这样做。

$file1 = '1.csv'; 
$file2 = '2.csv'; 
header('Content-Description: File Transfer'); 
header('Content-Type: text/comma-separated-values'); 
header('Content-Disposition: attachment; filename='.basename($file1, '.csv') . '-' . basename($file2, '.csv') . '.csv'); 
header('Content-Transfer-Encoding: binary'); 
header('Expires: 0'); 
header('Cache-Control: public'); 
header('Pragma: public'); 
header('Content-Length: ' . (filesize($file1) + filesize($file2))); 
ob_clean(); 
flush(); 
readfile($file1); 
readfile($file2); 

考虑使用多个文件的循环和心灵的Content-Type头的CSV文件的变化。

Answer 2

$file1 = '1.csv'; 
$file2 = '2.csv'; 
header('Content-Description: File Transfer'); 
header('Content-Type: application/jpeg'); 
header('Content-Disposition: attachment; filename="1-2.csv"'); 
header('Content-Transfer-Encoding: binary'); 
header('Expires: 0'); 
header('Cache-Control: public'); 
header('Pragma: public'); 
header('Content-Length: ' . (filesize($file1)+filesize($file2))); 
ob_clean(); 
flush(); 
echo file_get_contents($file1).file_get_contents($file2); 

的下载2项文件内容