我有以下JSON结构:如何迭代JSON结构?
[{ "id":"10", "class": "child-of-9" }, { "id": "11", "classd": "child-of-10" }]
如何遍历使用jQuery或JavaScript呢?
我有以下JSON结构:如何迭代JSON结构?
[{ "id":"10", "class": "child-of-9" }, { "id": "11", "classd": "child-of-10" }]
如何遍历使用jQuery或JavaScript呢?
从jQuery docs摘自:
var arr = [ "one", "two", "three", "four", "five" ];
var obj = { one:1, two:2, three:3, four:4, five:5 };
jQuery.each(arr, function() {
$("#" + this).text("My id is " + this + ".");
return (this != "four"); // will stop running to skip "five"
});
jQuery.each(obj, function(i, val) {
$("#" + i).append(document.createTextNode(" - " + val));
});
这是一个非常混乱的语法。你能解释一下吗?你还可以提供输出吗? – 2011-06-23 17:10:54
答案应该在JavaScript中给出,而不是JQuery。 – 2013-05-31 03:10:51
@WayneHartman我同情你的观点,但原来的问题确实会说“jquery或javascript”。似乎错误是没有在问题上的jQuery标签。 – vlasits 2014-01-13 18:39:47
MooTools的例子:
var ret = JSON.decode(jsonstr);
ret.each(function(item){
alert(item.id+'_'+item.classd);
});
您可以使用一个小型图书馆像物objx - http://objx.googlecode.com/
这样您可以编写代码:
var data = [ {"id":"10", "class": "child-of-9"},
{"id":"11", "class": "child-of-10"}];
// alert all IDs
objx(data).each(function(item) { alert(item.id) });
// get all IDs into a new array
var ids = objx(data).collect("id").obj();
// group by class
var grouped = objx(data).group(function(item){ return item.class; }).obj()
还有更多的“插件”可以让你处理这样的数据,请参见http://code.google.com/p/objx-plugins/wiki/PluginLibrary
var arr = [ {"id":"10", "class": "child-of-9"}, {"id":"11", "classd": "child-of-10"}];
for (var i = 0; i < arr.length; i++){
var obj = arr[i];
for (var key in obj){
var attrName = key;
var attrValue = obj[key];
}
}
var arr = [ {"id":"10", "class": "child-of-9"}, {"id":"11", "class": "child-of-10"}];
for (var i = 0; i < arr.length; i++){
document.write("<br><br>array index: " + i);
var obj = arr[i];
for (var key in obj){
var value = obj[key];
document.write("<br> - " + key + ": " + value);
}
}
注:该换的方法是凉的简单对象。与DOM对象一起使用不太聪明。
使用的foreach:
<html>
<body>
<script type="text/javascript">
var mycars = [{name:'Susita'}, {name:'BMW'}];
for (i in mycars)
{
document.write(mycars[i].name + "<br />");
}
</script>
</body>
</html>
会导致:
Susita
BMW
另一种解决方案通过JSON文件进行浏览JSONiq(在Zorba引擎实现),在那里你可以写类似:
let $json := [ {"id":"10", "class": "child-of-9"},
{"id":"11", "class": "child-of-10"} ]
for $entry in jn:members($json) (: binds $entry to each object in turn :)
return $entry("class") (: gets the value associated with "class" :)
您可以在http://www.zorba-xquery.com/html/demo#AwsGMHmzDgRpkFpv8qdvMjWLvvE=
运行它,如果这是您dataArray
:
var dataArray = [{"id":28,"class":"Sweden"}, {"id":56,"class":"USA"}, {"id":89,"class":"England"}];
则:
$(jQuery.parseJSON(JSON.stringify(dataArray))).each(function() {
var ID = this.id;
var CLASS = this.class;
});
随着嵌套的对象,可以检索由递归函数:
function inside(events)
{
for (i in events) {
if (typeof events[i] === 'object')
inside(events[i]);
else
alert(events[i]);
}
}
inside(events);
作为事件是json对象。
这是一个纯粹评论的JavaScript示例。
<script language="JavaScript" type="text/javascript">
function iterate_json(){
// Create our XMLHttpRequest object
var hr = new XMLHttpRequest();
// Create some variables we need to send to our PHP file
hr.open("GET", "json-note.php", true);//this is your php file containing json
hr.setRequestHeader("Content-type", "application/json", true);
// Access the onreadystatechange event for the XMLHttpRequest object
hr.onreadystatechange = function() {
if(hr.readyState == 4 && hr.status == 200) {
var data = JSON.parse(hr.responseText);
var results = document.getElementById("myDiv");//myDiv is the div id
for (var obj in data){
results.innerHTML += data[obj].id+ "is"+data[obj].class + "<br/>";
}
}
}
hr.send(null);
}
</script>
<script language="JavaScript" type="text/javascript">iterate_json();</script>// call function here
Marquis Wang's很可能是使用jQuery时的最佳答案。
这里的东西在纯JavaScript中非常相似,使用JavaScript的forEach
方法。 forEach以函数作为参数。然后将为该数组中的每个项目调用该函数,并将该项目作为参数。
短,操作简便:
<script>
var results = [ {"id":"10", "class": "child-of-9"}, {"id":"11", "classd": "child-of-10"}];
results.forEach(function(item) {
console.log(item);
});
</script>
请让我知道,如果它是不容易的:
var jsonObject = {
name: 'Amit Kumar',
Age: '27'
};
for (var prop in jsonObject) {
alert("Key:" + prop);
alert("Value:" + jsonObject[prop]);
}
var jsonString = "{\"schema\": {\"title\": \"User Feedback\", \"description\":\"so\", \"type\":\"object\", \"properties\":{\"name\":{\"type\":\"string\"}}}," +
"\"options\":{ \"form\":{\"attributes\":{}, \"buttons\":{ \"submit\":{ \"title\":\"It\", \"click\":\"function(){alert('hello');}\" }}} }}";
var jsonData = JSON.parse(jsonString);
function Iterate(data)
{
jQuery.each(data, function (index, value) {
if (typeof value == 'object') {
alert("Object " + index);
Iterate(value);
}
else {
alert(index + " : " + value);
}
});
};
Iterate(jsonData);
复制和http://www.w3schools.com粘贴,没有必要对JQuery的开销。
var person = {fname:"John", lname:"Doe", age:25};
var text = "";
var x;
for (x in person) {
text += person[x];
}
结果:李四25
http://stackoverflow.com/questions/1050674/fastest-way-to-iterate-through-json-string-in-javascript – Max 2009-07-03 07:11:57
“jQuery的或javascript” ? jquery是用javascript编写的! – 2014-08-28 12:09:13
它应该是“jQuery或纯JavaScript”。 – rsb2097 2015-09-17 11:16:41