如何使用LINQ直接选择属性值及其值较小的对象

Question

var req = (from k in dc.operations.ToList() 
      group k by k.id_employee into g 
      select new { id_emp = g.Key , nbr = g.Count(), } 
     ).Take(1).SingleOrDefault(); 

double mint=0; 
for (int i = 0; i < req.nbr; i++) 
{ 
    var r = (from l in dc.operations 
      where l.id_employee == req.id_emp 
      select l).Take(1).ToList(); 
    var r2 = (from l in dc.operations 
      where l.id_employee == req.id_emp 
      && l.date_operation.Value > r[i].date_operation.Value 
      select l).Take(1).ToList(); 
    double nbr_minut = (r[i].date_operation.Value - r2[i].date_operation.Value).TotalMinutes; 
    mint = +nbr_minut; 
    nbr_minut = 0; 
} 

TimeSpan span = TimeSpan.FromMinutes(mint); 
string nbr_houre = span.ToString(@"hh\:mm"); 

label1.Text = nbr_houre.ToString(); 

Answer 1

为了简化问题，可以说你有一个Person列表，并且想获得最年轻的人和他的年龄。
你可以这样做：

people.OrderBy(p => p.Age).Select(p => new {Dude = p, Age = p.Age}).FirstOrDefault();