模拟鼠标释放Pyqt

Question

如何使用Qt.SIGNAL来模拟鼠标释放动作？ 我需要在没有用户交互的情况下模拟mouseRelease。 在此先感谢！

Answer 1

下面是一个使用QPushButton的clicked信号的例子：

#!/usr/bin/env python 
#-*- coding:utf-8 -*- 

from PyQt4 import QtGui, QtCore 

class MyWindow(QtGui.QWidget): 
    def __init__(self, parent=None): 
     super(MyWindow, self).__init__(parent) 

     self.pushButtonSimulate = QtGui.QPushButton(self) 
     self.pushButtonSimulate.setText("Simulate Mouse Release!") 
     self.pushButtonSimulate.clicked.connect(self.on_pushButtonSimulate_clicked) 

     self.layoutHorizontal = QtGui.QHBoxLayout(self) 
     self.layoutHorizontal.addWidget(self.pushButtonSimulate) 

    @QtCore.pyqtSlot() 
    def on_pushButtonSimulate_clicked(self): 
     mouseReleaseEvent = QtGui.QMouseEvent(
      QtCore.QEvent.MouseButtonRelease, 
      self.cursor().pos(), 
      QtCore.Qt.LeftButton, 
      QtCore.Qt.LeftButton, 
      QtCore.Qt.NoModifier, 
     ) 

     QtCore.QCoreApplication.postEvent(self, mouseReleaseEvent) 

    def mouseReleaseEvent(self, event): 
     if event.button() == QtCore.Qt.LeftButton: 
      print "Mouse Release" 

     super(MyWindow, self).mouseReleaseEvent(event) 

if __name__ == "__main__": 
    import sys 

    app = QtGui.QApplication(sys.argv) 
    app.setApplicationName('MyWindow') 

    main = MyWindow() 
    main.show() 

    sys.exit(app.exec_()) 

Answer 2

可以使用：

from PyQt4.QtTest import QTest 

#(...) Where you want to release 
QTest.mouseRelease(widget_to_release, Qt.LeftButton) 

这将释放鼠标在窗口小部件的中心。

也有mousePress(),mouseClick()等的方法。但是，如果您正在测试在Windows上拖动&删除，请注意等效的QTest.mousePress()将被阻止，因为QDrag.exec_()阻止。