如何unnest序列规格？

Question

使用Clojure core.spec我可以有以下几种：

(s/conform (s/cat :a even? :b (s/* odd?) :a2 even? :b2 (s/* odd?)) [2 3 5 12 13 15]) 
=> {:a 2, :b [3 5], :a2 12, :b2 [13 15]} 

什么，我想有是外化的子规范删除冗余：

(s/def ::even-followed-by-odds 
    (s/cat :a even? :b (s/* odd?))) 

但

(s/conform (s/tuple ::even-followed-by-odds ::even-followed-by-odds) [2 3 5 12 13 15]) 
=> :clojure.spec/invalid 

这一个作品：

(s/conform (s/tuple ::even-followed-by-odds ::even-followed-by-odds) [[2 3 5] [12 13 15]]) 
=> [{:a 2, :b [3 5]} {:a 12, :b [13 15]}] 

所以，我正在寻找的是一个函数或宏（比如UNNEST），这将使它的工作：

(s/conform (s/tuple (unnest ::even-followed-by-odds) (unnest ::even-followed-by-odds)) [2 3 5 12 13 15]) 
=> [{:a 2, :b [3 5]} {:a 12, :b [13 15]}] 

如何才能得到呢？

Answer 1

你需要留在正则表达式运算土地：

(s/conform (s/cat :x ::even-followed-by-odds :y ::even-followed-by-odds) [2 3 5 12 13 15]) 

{:x {:a 2, :b [3 5]}, :y {:a 12, :b [13 15]}}