我不能让PHP postgre从PHP阵列new_address
执行插入一排,使用此代码:插入行PGSQL使用PDO
$customer_id = '2319';
$use_frequency = 1;
$sth = $dbh->prepare("
INSERT INTO address
('storeid',
'classtypeid',
'modifiedbyuser',
'modifiedbycomputer',
'modifieddate',
'seqid',
'issystem',
'isactive',
'streetaddress1',
'streetaddress2',
'city',
'state',
'county',
'postalcode',
'country',
'formattedtext',
'taxclassid',
'isvalidated',
'validatedaddress',
'hasvalidationerror',
'validationerror',
'customer_id',
'use_frequency')
VALUES (NULL,
NULL,
NULL,
NULL,
NULL,
NULL,
NULL,
NULL,
:address_1,
:address_2,
:city,
:state,
NULL,
:zip,
:country,
:formatted_text,
NULL,
NULL,
NULL,
NULL,
NULL,
:customer_id,
:use_frequency");
$sth->execute(array(
':address_1' => $new_address['address_1'],
':address_2' => $new_address['address_2'],
':city' => $new_address['city'],
':state' => $new_address['state'],
':zip' => $new_address['zip'],
':country' =>$new_address['country'],
':formatted_text' => $formatted_text,
':customer_id' => $customer_id,
':use_frequency' => $use_frequency
);
$sth->execute();
在表格的最后一栏是id
,这是一个serial
所以我省略了它,认为它会自动递增,但请告诉我,如果我错了。
我收到错误:
Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[42601]: Syntax error: 7 ERROR: syntax error at or near "'storeid'" LINE 3: ('storeid', ^' in
print_r($new_address);
显示我:
Array (
[0] => stdClass Object (
[customer_id] => 9319
)
[1] => stdClass Object (
[address_1] => 1515 example st
)
[2] => stdClass Object (
[address_2] => box 1
)
[3] => stdClass Object (
[city] => town
)
[4] => stdClass Object (
[state] => ST
)
[5] => stdClass Object (
[zip] => 12345
)
[6] => stdClass Object (
[country] => US
)
)
感谢您的咨询!
感谢。我改变了这一点。我现在得到错误:致命错误:带有消息'SQLSTATE [42601]的未捕获异常'PDOException':语法错误:7错误:输入结束时的语法错误行48:$ 9 ^'' – 1252748 2013-02-12 23:44:10
@thomas这将是最后一次线。在你的陈述中添加一个结束语“'''。 – 2013-02-12 23:46:57
啊哈。大。我现在(当然)得到以下错误:'序列地址_id_seq1'。这很奇怪。因为我没有名为'address_id_seq'的列。这可能是最后一个autoincrement'id'列的问题吗? – 1252748 2013-02-12 23:52:40