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Question

我想创建一个程序;然而，即使输入'y'或'yes'，代码仍会进入'n'/'no'循环。有什么建议么？

no = input("How many messages?") 
intNo = int(no) 
msgno = input("2 different msgs? [y/n]:") 
message = input("Message:") 
message2 = input("Message 2:") 

run = True 
pyautogui.click(x=980, y=805, button='left') 
while run == True: 
    if msgno.lower() == "n" or "no": 
     pyautogui.typewrite(message, interval=0.00001) 
     pyautogui.press('enter') 
     intNo = intNo - 1 
     if intNo <= 0: 
      run = False 
    elif msgno.lower() == "y" or "yes": 
     no = no/2 
     pyautogui.typewrite(message, interval=0.00001) 
     pyautogui.press('enter') 
     pyautogui.typewrite(message2, interval=0.00001) 
     pyautogui.press('enter') 
     intNo = intNo - 1 
     if intNo <= 0: 
      run = False 

Answer 1

您必须为每个If语句添加两个条件语句。像这样：if msgo.lower() == 'yes' or msgo.lower() == 'y'如果你只有一个存在的变量或一个值，它将默认为True，所以默认为“no”默认为True并进入代码块。