Knockoutjs有关的foreach孩子父母

Question

我有一个包含类型和名称地址2门阵列等等如下模型：

var model = [{"bstype":1},{"bstype":2},{"bstype":3},{"bstype":4}], 
    [{"bstype":1, "name":"John","Address":"Sample address"}, 
    [{"bstype":1, "name":"John","Address":"Sample address"}, 
    [{"bstype":3, "name":"John","Address":"Sample address"}, 
    {"bstype":2 ,"name":"John","Address":"Sample address"}]; 
    [{"bstype":2, "name":"John","Address":"Sample address"}, 
    [{"bstype":4, "name":"John","Address":"Sample address"}]; 

什么，我想要它做的是创建的列表：

类似于

I am not sure about this part how to implement it that is why it was gibberish. 
    bstype":1 will have a view of following 
    [{"bstype":1, "name":"John","Address":"Sample address"}, 
    [{"bstype":1, "name":"John","Address":"Sample address"}, 
    bstype"2: will have a view of following 
    {"bstype":2 ,"name":"John","Address":"Sample address"}]; 
    [{"bstype":2, "name":"John","Address":"Sample address"}, 
    bstype":3 has only one 
    [{"bstype":3, "name":"John","Address":"Sample address"}, 

等等等等。

我正在使用淘汰赛我检查了网站，它只讨论关于foreach但不知道如何访问子元素。

我希望这是有道理的。

由于

Answer 1

我把他们分开两个变种项第一个包含在所述第一阵列的第二的第二阵列。完成后，我使用第一个数组根据bstype循环4次。然后使用$ .root.secondarray循环遍历第二个项目。 谢谢大家。

Answer 2

的helper方法以两个数组组合成你有相同键来完成：

var model = [{"bstype":1},{"bstype":2},{"bstype":3},{"bstype":4}]; 

var modelChildren = [{"bstype":1, "name":"John","Address":"Sample address"}, 
    {"bstype":1, "name":"John","Address":"Sample address"}, 
    {"bstype":3, "name":"John","Address":"Sample address"}, 
    {"bstype":2 ,"name":"John","Address":"Sample address"}, 
    {"bstype":2, "name":"John","Address":"Sample address"}, 
    {"bstype":4, "name":"John","Address":"Sample address"}]; 

这种方法会给你一个新的数组匹配bstype“分组依据”：

var result = model.map(function(elem) 
      { 
       return { 
        bstype: elem.bstype, 
        children: modelChildren.filter(function(childElem) { 
         return childElem.bstype == elem.bstype; 
        }) 
       }; 
      });