2016-10-17 35 views
0

您好,我试图将多个选定的值存储在一个新的表中最后插入的ID。如何存储多个复选框,如果它们是动态的在php

我的错误是数组来了,但id_facility值不来

这里是我的形式:

<ul id="hostel_facility" class="dropdown-menu dropdown-select"> 
    <?php $facility = $conn->query("SELECT * FROM os_facilities ORDER BY id_facility ASC"); 
     while ($facilityresult = $facility->fetch_assoc()) { ?> 
     <li><a><input type="checkbox" name="hostel_facility[]" value="<?php echo$facilityresult['id_facility']; ?>" /><?php echo $facilityresult['facility_name']; ?></a></li> 
    <?php } ?> 
</ul> 

我想在新表中的列存储的id_hostel,id_facility

+1

我检查你的代码,它的工作。我检查'inspect'元素名称应该是'hostel_facility []'值'1'到'n'。你的pblm是什么? – Karthi

+0

已解决.. –

+0

你有什么错误? – Karthi

回答

0

我的形式:

<ul id="hostel_facility" class="dropdown-menu dropdown-select"> 
    <?php $facility = $conn->query("SELECT * FROM os_facilities ORDER BY id_facility ASC"); 
     while ($facilityresult = $facility->fetch_assoc()) { ?> 
     <li><a><input type="checkbox" name="hostel_facility[]" value="<?php echo $facilityresult['id_facility']; ?>" /><?php echo $facilityresult['facility_name']; ?></a></li> 
    <?php } ?> 
</ul> 

这里是存储作业后,我的控制器页:

$hostelId=$conn->insert_id; 
if($addHostel) 
{ 
foreach($hostelData['hostel_facility'] as $key=>$facility) 
{ 
    $conn->query("INSERT INTO os_hostel_facility (id_hostel,id_facility) values ('".$hostelId."','".$facility."')"); 
} 
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