从字符串列表创建类实例列表py2.7

Question

我的代码只创建最后一个实例时间len（list）我如何改变这个来创建每个实例分离？ ：|

@staticmethod 
def impWords(): 
    tempFile = open('import.txt','r+') 
    tempFile1 = re.findall(r'\w+', tempFile.read()) 
    tempFile.close() 

    for i in range(0,len(tempFile1)): 

     word.ID = i 
     word.data = tempFile1[i] 
     word.points = 0 
     Repo.words.append(word) 
     word.prt(word) 
    print str(Repo.words) 
    UI.Controller.adminMenu() 

Answer 1

假设word是Word一个实例，你应该创建一个新的在每次迭代中，像这样：

@staticmethod 
def impWords(): 

    with open('import.txt','r+') as tempFile: 
     #re 
     tempFile1 = re.findall(r'\w+', tempFile.read()) 
     # using enumerate here is cleaner 
     for i, w in enumerate(tempFile1): 
      word = Word() # here you're creating a new Word instance for each item in tempFile1 
      word.ID = i 
      word.data = w 
      word.points = 0 
      Repo.words.append(word) 
      word.prt(word) # here it would be better to implement Word.__str__() and do print word 

    print Repo.words # print automatically calls __str__() 
    UI.Controller.adminMenu() 

现在，如果你Word类__init__需要ID，data和points作为参数，和Repo.words是一个列表，你可以减少到：

@staticmethod 
def impWords(): 

    with open('import.txt','r+') as tempFile: 
     #re 
     tempFile1 = re.findall(r'\w+', tempFile.read()) 
     # using enumerate here is cleaner 
     Repo.words.extend(Word(i, w, 0) for i, w in enumerate(tempFile1)) 

    print Repo.words # print automatically calls __str__() 
    UI.Controller.adminMenu()