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我是新人,在陡峭的曲线上学习IDL。我有2 PROS第一个如下IDL编程语言中的调用例程
Pro READ_Netcdf1,infile,temperature,time,print_prompts=print_prompts
COMPILE_OPt IDL2
infile='D:/Rwork/dataset/monthly_mean/version_2C/air.2m.mon.mean.nc'
IF (N_Elements(infile) EQ 0) Then STOP,'You are being silly, you must specify infile on call'
print,infile
iid = NCDF_OPEN(infile)
NCDF_VARGET, iid, 'time', time ; Read time
NCDF_VARGET, iid, 'air', temperature ; Read surface average temperature
NCDF_VARGET, iid, 'lat', latitude ; Read Latitude
NCDF_VARGET, iid, 'lon', longitude ; Read Longitude
NCDF_CLOSE, iid ; Close Input File
Centigrade=temperature-273.15
print,'Time'
print,time[0:9]
Print, 'Latitude'
Print, latitude[0:9]
Print, 'Longitude'
Print, longitude[0:9]
print,'Temperature'
print, temperature[0:9]
Print, 'Centigrade'
Print, Centigrade[0:9]
;ENDIF
RETURN
END
这完美的作品。我的第二个专业如下: -
PRO Change_Kelvin_to_Cent,Temperature
;+ This programme take the temperature from the NETCDF file and converts
; to Centigrade
;Output
; The Month Mean Temperature in Centigrade
; Must have read ncdf1 in the directory run first
;
; -
COMPILE_OPt IDL2
infile='D:/Rwork/dataset/monthly_mean/version_2c/air.2m.mon.mean.nc'
read_netcdf1, infile, Temperature
Centigrade = Temperature-273.15
print,'Centigrade'
print,Centigrade[0:9]
RETURN
END
这也适用 我被指示致电从第一PRO变量“温度”来计算第二PRO 温度不命令行
read_netcdf1,infile,温度
我不能得到这个工作。任何人都可以建议并帮助我解决这个问题请