没有结果ASP REPLACE函数

Question

varitem = match.SubMatches（1） varitemthis = p_variables_list.Item（varitem）结果的

response.write match.Value &" "& varitemthis &" "&varitem & "<br>" 

是

{{name}} rrrr name 
{{site_root}} www.site.com/ site_root 
{{mail}} sdddddsssdfffrrrsdf@ssrsssr.com mail 
{{code}} code 

结果

p_template = Replace(p_template, match.Value, varitem) 
response.write p_template 

没事，但

p_template = Replace(p_template, match.Value, varitemthis) 
response.write p_template 

什么......为什么？怎么了？

Answer 1

几件事情......

记住替换功能是区分大小写的

不要通过确保您有价值观的一些基本故障排除。

Response.Write "Original p_template = " & p_template 
Response.Write "match.Value = " & match.Value 
Response.Write "varitemthis = " & varitemthis 

p_template = Replace(p_template, match.Value, varitemthis) 

Response.Write "New p_template = " & p_template 

Answer 2

在传统的ASP的更换功能不区分大小写。