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我试图保存一个可折叠菜单的状态,并使用jQuery Cookie插件..到目前为止我遇到了麻烦..虽然..任何帮助吗?用cookie和jquery保存UI状态
,它的折叠/展开
<script type="text/javascript">
$(document).ready(function() {
$(".login-holder > ul > .loginTitle").click(function() {
$(this).parent().find("li").slideToggle("fast");
if ($(this).parent().find(".toggle").html() == "+") {
$(this).parent().find(".toggle").html("-");
} else {
$(this).parent().find(".toggle").html("+");
}
});
})
</script>
XHTML的,我已经做到了这一点使用cookie
<ul class="account-links">
<div class="loginTitle">User Options<span class="toggle">-</span></div>
<div class="menuLinks">
<li>
<%= Html.ActionLink<EventController>(x => x.List(), "Events Near Me")%>
</li>
<li>
<%= Html.ActionLink<MyEventsController>(x => x.List(), "My Events")%>
</li>
<li>
<%= Html.ActionLink<AccountController>(x => x.Edit(), "My Profile")%>
</li>
<li>
<%= Html.ActionLink<ClubController>(x => x.List(), "Clubs Near Me")%>
</li>
<li>
<%= Html.ActionLink<MyClubsController>(x => x.List(), "My Clubs")%>
</li>
<li>
<%= Html.ActionLink<AccountController>(x => x.ChangePassword(), "Change My Password")%>
</li>
<li>
<%= Html.ActionLink<DependantController>(x => x.List(), "My Dependants") %>
</li>
</div>
</ul>
</div>
<% if (ViewModel.Profile.HasOrganizerInfo) { %>
<div class="login-holder">
<ul class="account-links">
<div class="loginTitle">Organizer Details<span class="toggle">-</span></div>
<div class=menuLinks>
<li>
<%= Html.ActionLink<AccountController>(x => x.Organizer(), "Organizer Details")%>
</li>
<li>
<%= Html.ActionLink<EventController>(x => x.Edit(default(int?)), "Post An Event")%>
</li>
<li>
<%= Html.ActionLink<EventAdminController>(x => x.List(), "Events Created By Me") %>
</li>
<li>
<%= Html.ActionLink<ClubController>(x => x.Edit(default(int?)), "Create A Club")%>
</li>
<li>
<%= Html.ActionLink<ClubAdminController>(x => x.List(), "Clubs Created By Me")%>
</li>
</div>
</ul>
</div>
<% } %>
我根本没有在代码中看到任何对cookie的引用,我是否错过了一些东西?对于性能,可读性和可维护性,您应该在本地存储此引用:$(this).parent()。find(“。toggle”)(例如var foo =; foo.html())。 –
MightyE
2010-12-20 13:55:38
嗯,我有困难,所以我认为我应该把一个干净的副本在那里没有参考,所以它没有浑浊的情况 – Kevin 2010-12-20 13:57:46