2015-02-24 97 views
1

我习惯于在python 2.7中工作,所以出现了一些新的东西,例如print函数不同。所以请原谅我的无知。我对编程也很新颖。Python 3.4.1脚本语法错误,arcpy&

因此,这里是我的脚本,我不断收到这突出一些逗号或空格错误,说有一个

SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 16-17: malformed \N character escape 

代码:

import arcpy 

print("mosaic to new raster starting!") 

env.workspace = "F:\GDAL" 
arcpy.env.pyramid = "NONE" 
arcpy.env.rasterStatistics = "NONE" 
arcpy.env.compression = "JPEG 87" 
arcpy.env.tileSize = "256 256" 

print("Environment set") 

RasterInput = "m_3511401_ne_11_1_20130731.jpg;m_3511401_nw_11_1_20130731.jpg;m_3511401_se_11_1_20130731.jpg;m_3511401_sw_11_1_20130731.jpg;" 

print("Input set") 

arcpy.MosaicToNewRaster_management(RasterInput,"F:\Pro_Projects\NAIP2013\raster.sde","MosaicFile1","","8_BIT_UNSIGNED","","3","LAST","FIRST") 

print("mosaic done!") 
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我觉得问题是你不逃避文件路径中的字符,特别是反斜杠。请参阅http://stackoverflow.com/questions/3380484/using-backslash-in-python-not-to-escape。 – sovemp 2015-02-24 21:04:31

回答

3

反斜杠(使用你的Windows路径分隔符)Python字符串中的信号转义序列。双倍的反斜线或使用原始字符串字面量:

"F:\\Pro_Projects\\NAIP2013\\raster.sde" 

r"F:\Pro_Projects\NAIP2013\raster.sde" 

Windows还接受向前斜杠的路径,避免了问题完全:

"F:/Pro_Projects/NAIP2013/raster.sde" 
+0

DOH!就是这样!谢谢! – user3161018 2015-02-24 21:18:16