1
在我的控制器之一,我有以下几点:Laravel通过中间型号预先加载
return Lot::with(array('region', 'territory', 'manager')) -> get();
这完美的作品,并返回如下:
Array
(
[0] => stdClass Object
(
[id] => 1
[region_id] => 3
[territory_id] => 2
[state_id] => 5
[manager_id] => 2
[lot_num] => 0
[lot_type] => managed
[name] => Some Name
[address_1] => Some Address
[address_2] =>
[address_3] =>
[city] => Some City
[zip] => 00000
[opened_at] =>
[deleted_at] =>
[created_at] => 2014-11-06 00:49:39
[updated_at] => 2014-11-06 00:49:39
[region] => stdClass Object
(
[id] => 3
[name] => Corporate
[deleted_at] =>
[created_at] => 2014-11-06 00:49:39
[updated_at] => 2014-11-06 00:49:39
)
[territory] => stdClass Object
(
[id] => 2
[name] => Corporate
[deleted_at] =>
[created_at] => 2014-11-06 00:49:39
[updated_at] => 2014-11-06 00:49:39
)
[manager] => stdClass Object
(
[id] => 2
[email] => [email protected]
[active] => 1
[last_login] =>
[created_at] => 2014-11-06 00:49:39
[updated_at] =>
[deleted_at] =>
)
)
)
我的“经理”的方法该地块类有如下关系:
return $this -> belongsTo('User');
我的用户类别上有以下方法:
public function profile(){
return $this -> hasOne('Profile');
}
现在,终于我的问题:)是否有可能急于加载该用户通过预先加载,我在第一个代码剪断做我的很多课的个人资料?我想要做到的是有我的“经理”对象的回报是这个样子:
[manager] => stdClass Object
(
[id] => 2
[email] => [email protected]
[active] => 1
[last_login] =>
[created_at] => 2014-11-06 00:49:39
[updated_at] =>
[deleted_at] =>
[profile] => stdClass Object
(
[id] => 5
[first_name] => Test
[last_name] => Tester
...
)
)
真棒...谢谢! – dxhans5 2014-11-06 17:50:30
亿上传...谢谢Razor – dangel 2015-09-06 00:42:15