我试图获取URL的HTML源代码,解析它,然后将结果打印为PDF。Python - 获取URL,解析并打印PDF
为此,我想依赖BeautifulSoup,urllib2和reportlab,但我缺乏如何正确合并它们的方法。
作为错误,我运行django 1.3.1 dev服务器并访问视图时得到了'module' object is not callable
。
这是我的代码:
from reportlab.pdfgen import canvas
from cStringIO import StringIO
from django.http import HttpResponse
from django.shortcuts import render_to_response
from django.template import RequestContext
# Fetching the URL
import urllib2
# Parsing the HTML
from BeautifulSoup import BeautifulSoup
# The ConverterForm
from django import forms
class ConverterForm(forms.Form):
# Use textarea instead the default TextInput.
html_files = forms.CharField(widget=forms.Textarea)
filename = forms.CharField()
# Create your views here.
def create_pdf(request):
# If the form has been submitted
if request.method == 'POST':
# A form bound to the POST data
form = ConverterForm(request.POST)
# All validation rules pass
if form.is_valid():
# PDF creation process
# Assign variables
html_files = form.cleaned_data['html_files']
filename = form.cleaned_data['filename']
# Create the HttpResponse object with the appropriate PDF headers.
response = HttpResponse(mimetype='application/pdf')
# The use of attachment forces the Save as dialog to open.
response['Content-Disposition'] = 'attachment; filename=%s.pdf' % filename
buffer = StringIO()
# Get the page source
page = urllib2.urlopen(html_files)
html = page.read()
# Parse the page source
soup = BeautifulSoup(html)
# Create the PDF object, using the StringIO() object as its "file".
p = canvas.Canvas(buffer)
# Draw things on the PDF and generate the PDF.
# See ReportLab documentation for full list of functions.
p.drawString(100, 100, soup)
# Close the PDF object cleanly.
p.showPage()
p.save()
# Get the value of the StringIO buffer and write it to the response.
pdf = buffer.getvalue()
buffer.close()
response.write(pdf)
return response
else:
# An unbound form
form = ConverterForm()
# For RequestContext in relation to csrf see more here:
# https://docs.djangoproject.com/en/1.3/intro/tutorial04/
return render_to_response('converter/index.html', {
'form': form,
}, context_instance=RequestContext(request))
你从哪里得到错误?请全部显示。你甚至没有显示你的整个代码。 – Marcin 2012-03-24 13:08:04
我编辑了代码。对不起,最初我以为其余的可能不相关。 Registers – orschiro 2012-03-24 13:13:10
你确切的错误是'buffer = StringIO()',这应该是'buffer = StringIO.StringIO()',但我提供了一个更简单的解决方案作为答案。 – 2012-03-24 14:27:57