2014-11-04 101 views
1

在我的应用程序中,我想使用UPDATE命令来更新多个MySQL列。我用下面的代码尝试了它,但我知道它确实不安全。因为它导致了SQL注入攻击。但我不知道如何编写带有参数的查询来更新多个MySQL列。使用参数化更新命令更新多个mysql列

这是我的代码:

string constring = string.Format("datasource='{0}';port='{1}';database='{2}';username=claimsprologin;password=xxxxxxxxxxxxxxxx;Connect Timeout=180;Command Timeout=180", serveriplable.Text, portno.Text, databasenamelable.Text); 
string Query = "update claimloans set loannumber= '" + this.loannumbertextbox.Text.Trim() + " ', pool = '" + this.loanpooltextbox.Text.Trim() + "' , disblid = '" + this.disbidtextbox.Text.Trim() + "' , category = '" + this.categorytxtbox.Text.Trim() + " ', subcacategory = '" + this.subcategorytxtbox.Text.Trim() + " ', invoice = '" + this.invoicenumbertextbox.Text.Trim() + " ', invoicedate = '" + this.invoicedatetextbox.Text.Trim() + " ', docs = '" + this.docscombobox.Text.Trim() + "' , where username = '" + this.usernamelable.Text.Trim() + "' ;"; 
MySqlConnection conwaqDatabase = new MySqlConnection(constring); 
MySqlCommand cmdwaqDatabase = new MySqlCommand(Query, conwaqDatabase); 
MySqlDataReader myreader; 

try { 
    conwaqDatabase.Open(); 
    myreader = cmdwaqDatabase.ExecuteReader(); 
    while (myreader.Read()) { } 

    MessageBox.Show("Credential informations are updated"); 

    conwaqDatabase.Close(); 
} 

catch { 

} 
+0

为什么不使用参数化查询? – vortex 2014-11-04 14:22:36

回答

0

您可以使用这样的事情。您在您的sql命令中添加占位符,然后在运行ExecuteReader之后添加参数值。

string constring = string.Format("datasource='{0}';port='{1}';database='{2}';username=claimsprologin;password=gfx)C#G$aD3bL`@;Connect Timeout=180;Command Timeout=180", serveriplable.Text, portno.Text, databasenamelable.Text); 
string Query = "update claimloans set loannumber= @loannumbertextbox, pool = @loanpooltextbox, disblid = @disbidtextbox, category = @categorytxtbox, subcacategory = @subcategorytxtbox, invoice = @invoicenumbertextbox, invoicedate = @invoicedatetextbox, docs = @docscombobox, where username = @usernamelable;"; 
MySqlConnection conwaqDatabase = new MySqlConnection(constring); 
MySqlCommand cmdwaqDatabase = new MySqlCommand(Query, conwaqDatabase); 

cmdwaqDatabase .Parameters.AddWithValue("@loannumbertextbox", this.loannumbertextbox.Text.Trim()); 
+0

谢谢先生,我从你的指导中学到了很多东西 – 2015-02-20 13:44:29