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我已经拥有变量JSON编码,然后像“[”和“]”在json数组中有元素。问题是?如何删除元素。如何在json中删除元素数组“[”&“]”?
这是改变前的JSON的示例
[{
"form": {
"user_id": "1",
"form_id": 26,
"form_name": "KireniuS",
"form_description": "afafasf",
"form_json": [{
"id": 72043,
"name": "EditText",
"input_type": "text",
"hint": "",
"options": ""
}, {
"id": "409289",
"name": "Ini Spinner",
"input_type": "spinner",
"hint": "ini saya ro",
"options": "Saya, dan Dia"
}],
"created_at": "17-10-2014_16:49",
"created_by": "adminweb",
"last_updated_at": "17-10-2014_16:49"
}
}]
PHP:
$jadi_json = array();
foreach($model as $row)
{
$json_converter = json_decode($row->json_form);
$saya = array(
"form"=>array(
"user_id"=>$row->id_user,
"form_id"=>$row->id_form,
"form_name"=>$row->form_name,
"form_description"=>$row->form_description,
"form_json"=>$json_converter->form_json,
"created_at"=>$row->created_at,
"created_by"=>$row->created_by,
"last_updated_at"=>$row->last_updated_at
));
array_push($jadi_json, $saya);
}
header('Content-Type: application/json');
echo json_encode($jadi_json);
JSON格式所需
{
"form": {
"user_id": "1",
"form_id": 26,
"form_name": "KireniuS",
"form_description": "afafasf",
"form_json": [{
"id": 72043,
"name": "EditText",
"input_type": "text",
"hint": "",
"options": ""
}, {
"id": "409289",
"name": "Ini Spinner",
"input_type": "spinner",
"hint": "ini saya ro",
"options": "Saya, dan Dia"
}],
"created_at": "17-10-2014_16:49",
"created_by": "adminweb",
"last_updated_at": "17-10-2014_16:49"
}
}
元件阵列 “[” 和 “]” 被省略只是表面上。
所以你想要一个单一的对象而不是一个对象数组吗?只需从数组中取出第一个索引元素,就是这样,要么我不理解你的问题,要么你不懂JSON。 .. – 2014-10-17 10:42:08
'$ new_json = $ old_json [0]'?或者我错过了什么? – danneth 2014-10-17 10:47:39