嘿,我写了这个deleteNode()方法,如果我使用数字(int),但不会当我尝试传递一个字符串时工作。我打印出一个字符串[]名单的列表,我试图从列表中删除某个名字。当我输入名称时,它会打印“找不到节点”。就像我说的,如果我打印出一个数字列表,它的效果很好,但如果我改变并打印一个字符串,它不会。任何帮助表示赞赏。如何从链表中删除一个节点
public class BigNode {
public String dataitems;
public BigNode next;
BigNode front ;
public void initList(){
front = null;
}
public BigNode makeNode(String number){
BigNode newNode;
newNode = new BigNode();
newNode.dataitems = number;
newNode.next = null;
return newNode;
}
public boolean isListEmpty(BigNode front){
boolean balance;
if (front == null){
balance = true;
}
else {
balance = false;
}
return balance;
}
public BigNode findTail(BigNode front) {
BigNode current;
current = front;
while(current.next != null){
//System.out.print(current.dataitems);
current = current.next;
} //System.out.println(current.dataitems);
return current;
}
public void addNode(BigNode front ,String number){
BigNode tail;
if(isListEmpty(front)){
this.front = makeNode(number);
}
else {
tail = findTail(front);
tail.next = makeNode(number);
}
}
public void deleteNode(BigNode front, String value) {
BigNode curr, previous = null; boolean found;
if (!isListEmpty(front)){
curr = front;
found = false;
while ((curr.next != null) && (!found)) {
if(curr.dataitems.equals(value)) {
found = true;
}
else {
previous = curr;
curr = curr.next;
}
}
if (!found) {
if(curr.dataitems.equals(value)) {
found = true;
}
}
if (found) {
if (curr.dataitems.equals(front.dataitems)){ // front.dataitems may be wrong .dataitems
front = curr.next;
} else {
previous.next = curr.next;
}
} else {
System.out.println("Node not found!");
//curr.next = null; // Not sure If this is needed
}
}
showList(front);
}
public void printNodes(String[] len){
int j;
for (j = 0; j < len.length; j++){
addNode(front, len[j]);
} showList(front);
}
public void showList(BigNode front){
BigNode current;
current = front;
while (current.next != null){
System.out.print(current.dataitems + ", ");
current = current.next;
}
System.out.println(current.dataitems);
}
public static void main(String[] args) {
String[] names = {"Billy Joe", "Sally Mae", "Joe Blow", "Tasha Blue"};
BigNode x = new BigNode();
x.printNodes(names);
Scanner in = new Scanner(System.in);
String delete = in.next();
x.deleteNode(x.front, delete);
}
的String []名称= {1,名称2,名称3,名称4}
- 首先它打印列表,然后要求删除什么名字。
确定继承人的大部分代码 – TMan