语义错误，Symfony的DQL

我有一个与MySQL通常执行的查询：语义错误，Symfony的DQL

SELECT * 
FROM td_user u 
JOIN td_ranking ranking ON ranking.user_id = u.id 
JOIN (
SELECT x.user_id, 
MAX(x.id) AS default_id 
FROM td_ranking x 
GROUP BY x.user_id 
) y 
ON y.user_id = ranking.user_id 
AND y.default_id = ranking.id

我试图改变它在DQL的运行它的Symfony：

$query = $this->_em->createQuery(' 
    SELECT u.*,ranking.* 
    FROM UserBundle:User u 
    JOIN UserBundle:Ranking ranking 
    WITH ranking.user_id = u.id 
    JOIN (
    SELECT x.user_id, MAX(x.id) AS default_id 
    FROM UserBundle:Ranking x 
    GROUP BY x.user_id 
) y 
    ON y.user_id = ranking.user_id 
    AND y.default_id = ranking.id' 
); 
$results = $query->getResult();

我有这样的错误：

[语义错误] 0行，列113 '附近（SELECT x.user_id，'：错误：类 '（' 没有定义

你有什么想法吗？谢谢！

来源

2017-01-02 Tom59

您不必为排名实体USER_ID财产。 –

哦，是的......但如何做到这一点？我尝试这一点，但结果是一样的：“ 选择U *，*排名从 UserBundle：用户U JOIN UserBundle：排名排名 WITH ranking.user_id = u.id JOIN（ SELECT x.user ，MAX（x.id）AS default_id FROM UserBundle：Ranking x GROUP BY x.user）y ON y.user = ranking.user AND y.default_id = ranking.id“ – Tom59

事实上，我有一个OneToMany用户与排名的关系。许多排名可以链接到用户。在我的要求中，我想获取每个用户的最后排名......您有想法吗？ – Tom59

使用本地查询

$rsm = new ResultSetMapping(); 
$sql = " 
    SELECT * 
FROM td_user u 
JOIN td_ranking ranking ON ranking.user_id = u.id 
JOIN (
SELECT x.user_id, 
MAX(x.id) AS default_id 
FROM td_ranking x 
GROUP BY x.user_id 
) y 
ON y.user_id = ranking.user_id 
AND y.default_id = ranking.id 
"; 

$result = $this->getEntityManager()->createNativeQuery($sql, $rsm)->getResult();

来源

2017-01-02 14:15:38

谢谢！但是，我有这样的错误：无法找到名称为“ SELECT * FROM ütd_user JOIN 排名td_ranking ON ranking.user_id = u.id JOIN（SELECT x.user_id， MAX（x.id一个名为原生查询）AS default_id FROM td_ranking x GROUP BY x.user_id）y ON y.user_id = ranking.user_id AND y.default_id = ranking.id“ – Tom59

请使用更新的ans –

@ Tom59请使用更新的ans。 –

语义错误，Symfony的DQL

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