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用户必须在URL中传入一个查询字符串,该字符串将返回不同的分页,如果他没有输入任何一个或两个查询,结果将会改变。下面的代码在CakePHP中起作用,但它看起来很可怕,如果没有这些条件,还有更好的方法来实现我想要做的事情吗?与查询字符串不同的分页条件[CakePHP 3]
if($this->request->query('date'))
{
$this->paginate = [
'conditions' => [
'Reservations.id_venue' => $this->Auth->user('id_venue_manager'),
'Reservations.date' => $this->request->query('date'),
],
];
}
else if($this->request->query('id_user'))
{
$this->paginate = [
'conditions' => [
'Reservations.id_venue' => $this->Auth->user('id_venue_manager'),
'Reservations.id_user' => $this->request->query('id_user'),
],
];
}
else if($this->request->query('id_user') && $this->request->query('date'))
{
$this->paginate = [
'conditions' => [
'Reservations.id_venue' => $this->Auth->user('id_venue_manager'),
'Reservations.id_user' => $this->request->query('id_user'),
'Reservations.date' => $this->request->query('date'),
],
];
}
else
{
$this->paginate = [
'conditions' => [
'Reservations.id_venue' => $this->Auth->user('id_venue_manager'),
],
];
}
我会用这个插件,而不是https://github.com/FriendsOfCake/search :) – burzum