我在Android的初学者,我有以下代码: Android的PHP - 存储会话到MySQL数据库
session_start();
$username = $_POST['username'];
$password = $_POST['password'];
$query = mysql_query("SELECT * FROM users WHERE c_name='$username' AND c_password='$password'") or die("Could not run query!");
$rows = mysql_num_rows($query);
if($rows == 0){
echo "No user was found";
}else{
$row = mysql_fetch_assoc($query);
$_SESSION['id'] = $row['id'];
$_SESSION['username'] = $row['c_name'];
echo "User Found";
}
在文件(在PHP端,用户登录到我的Android应用程序后)在这里我想获得我的人是登录的用户的ID有:
session_start();
$r_name = $_POST['r_name'];
$r_address = $_POST['r_address'];
$r_phone = $_POST['r_phone'];
$r_username = $_POST['r_username'];
$req_id = $_SESSION['id'];
$req_username = $_SESSION['username'];
$query_add = "INSERT INTO data_collection VALUES ('','$r_name','$r_address','$r_phone','$r_username','$req_id')";
$query_exec = mysql_query($query_add) or die("Could not insert to db");
if($query_exec){
echo "Success";
}else
echo "Error in query";
和Android端的数据帖到2 PHP文件:
public void onClick(View v) {
// TODO Auto-generated method stub
String s_res_name = res_name.getText().toString();
String s_res_address = res_address.getText().toString();
String s_res_phone = res_phone.getText().toString();
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("r_name", s_res_name));//c_name is the value in PHP and in the mySQL db
nameValuePairs.add(new BasicNameValuePair("r_address", s_res_address));
nameValuePairs.add(new BasicNameValuePair("r_phone", s_res_phone));
try{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://10.0.2.2/thesis/data_collection.php");
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
ResponseHandler<String> responseHandler = new BasicResponseHandler();
final String response = httpclient.execute(httppost,responseHandler);
tv.setText(""+response);
if (response.equals("Success")){
Toast toast = Toast.makeText(getApplicationContext(), "Data Collection task successfully created", Toast.LENGTH_LONG);
toast.show();
finish();
}
}catch(Exception e){
Log.e("log.tag","Error in http connection"+e.toString());
}
}
});
如何获取第二个php文件中的会话ID并将其存储在新表中? 这段代码运行良好,通过网络,当我通过表格发布数据,但在android侧它不...
谢谢你的帮助。
实际上你的问题是什么,$ req_id = $ _SESSION ['id'];您已获得会话ID – 2013-05-05 17:41:35
您的问题是插入表格还是获取会话ID – 2013-05-05 17:42:02
您好。我强烈建议使用Cookie来管理您的用户数据。 – 2013-05-05 17:42:17