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我可以从eclipse导出到.war文件并在Tomcat上运行。但是,当我使用Bazel构建它时,生成的.war文件不会在Tomcat上运行。Bazel war文件的无效'./'目录
项目结构从日食(和工作)出口
project
|_src
| |_main/java/*.java
|
|_WebContent
|_META-INF
|_Manifest.mf
|_WEB-INF
|_lib/*.jar
|_web.xml
战争文件看起来像这样:
inflated: META-INF/MANIFEST.MF
inflated: .DS_Store
created: META-INF/
created: WEB-INF/
created: WEB-INF/classes/
created: WEB-INF/classes/main/
created: WEB-INF/classes/main/java/
inflated: WEB-INF/classes/main/java/.DS_Store
inflated: WEB-INF/classes/main/java/foo.class
inflated: WEB-INF/classes/main/.DS_Store
inflated: WEB-INF/classes/.DS_Store
inflated: WEB-INF/.DS_Store
created: WEB-INF/lib/
inflated: WEB-INF/lib/.DS_Store
inflated: WEB-INF/lib/jersey-bundle-1.19.jar
inflated: WEB-INF/web.xml
当我创建巴泽勒一个.war,我得到这个:
created: ./
created: ./WEB-INF/
created: ./WEB-INF/classes/
created: ./WEB-INF/classes/main/
created: ./WEB-INF/classes/main/java/
inflated: ./WEB-INF/classes/main/java/.DS_Store
inflated: ./WEB-INF/classes/main/java/foo.class
created: ./WEB-INF/lib/
inflated: ./WEB-INF/lib/jersey-bundle-1.19.jar
inflated: ./WEB-INF/web.xml
我正在自定义.bzl文件以获取war文件下面的代码:
def _war_impl(ctxt):
zipper = ctxt.file._zipper
data_path = ctxt.attr.data_path
war = ctxt.outputs.war
build_output = war.path + ".WEB-INF"
print("build_output = %s" % (build_output))
cmd = [
"set -e;rm -rf " + build_output,
"mkdir -p %s" % build_output
]
inputs = ctxt.files.jars + [zipper]
cmd += ["mkdir -p %s/WEB-INF/lib" % build_output]
cmd += ["mkdir -p %s/WEB-INF/classes/main/java" % build_output]
谁能指出如何使用“的mkdir”,使其不产生WAR文件中建立“./”目录?