这是什么代码,我用标记行(BOLD)得到问题,我认为这是因为jar版本,但我不确定这一点。如果这是因为jar版本,请让我知道正确的一个。不兼容的类型,并不能在twitter4j中找到符号?
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import twitter4j.Twitter;
import twitter4j.TwitterException;
import twitter4j.TwitterFactory;
import twitter4j.auth.AccessToken;
import twitter4j.auth.RequestToken;
public class NamexTweet {
private final static String CONSUMER_KEY = "xxxxxxxxxxxxx";
private final static String CONSUMER_KEY_SECRET = "yyyyyyyyyyyyyyy";
public void start() throws TwitterException, IOException {
Twitter twitter = new TwitterFactory().getInstance();
twitter.setOAuthConsumer(CONSUMER_KEY, CONSUMER_KEY_SECRET);
**RequestToken requestToken = twitter.getOAuthRequestToken();**
System.out.println("Authorization URL: \n"
+ requestToken.getAuthorizationURL());
AccessToken accessToken = null;
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
while (null == accessToken) {
try {
System.out.print("Input PIN here: ");
String pin = br.readLine();
**accessToken = twitter.getOAuthAccessToken(requestToken, pin);**
} catch (TwitterException te) {
System.out.println("Failed to get access token, caused by: "
+ te.getMessage());
System.out.println("Retry input PIN");
}
}
System.out.println("Access Token: " + accessToken.getToken());
System.out.println("Access Token Secret: "
+ accessToken.getTokenSecret());
twitter.updateStatus("hi.. im updating this using Namex Tweet for Demo");
}
public static void main(String[] args) throws Exception {
new NamexTweet().start();// run the Twitter client
}
}
但什么_is_这些问题行呢? – yair 2012-03-07 12:54:29
我得到不兼容的类型,并且不能在代码中出现错误的符号错误 – SAR 2012-03-07 12:55:24
您正在使用哪个版本的twitter4j? – Jeroen 2012-03-07 13:26:46