Cakephp保存相关模型数据创建一个字段的空白记录

Question

我一直试图弄清楚这个问题整个上午。尝试了其他问题的一些事情，但它要么不适用于我的情况，要么不适用。我有两个表：

用户 =（ID，姓名，用户名，密码，角色，last_edit，语言）
french_translations =（ID，french_clinical_recommendations，french_tradenames，include_drug，french_category，drug_id，USER_ID）

用户有许多法语翻译和法语翻译belongsTo用户。

当用户添加或编辑french_translation时，我希望它将用户ID保存在french_translations表中的该字段user_id中，然后将该药物的通用名称放入users表的last_edit字段中。现在它在每个表格中创建一个新记录。在用户表中，除了id和last_edit字段（其将正确的药物名称放在字段中）之外，一切都是空白的。而french_translations表有空白的记录，user_id与users表中创建的空白表相同。

控制器：

function add($id = null) { 
    $userid = $session->read('Auth.User.id'); 
    $drug = $this->FrenchTranslation->Drug->read(
     array(
      'Drug.id','Drug.generic','Drug.ahl','Drug.aap','Drug.rid','Drug.oral','Drug.mw','Drug.clinical_recommendations', 
      'Drug.category','Drug.lrc' 
    ), 
     $id 
    ); 
    $this->set('user',$userid); 
    $this->set('drug',$drug); 

    if (!empty($this->data)) { 
     $french_translation['FrenchTranslation']['id'] = $this->Session->read('id'); 
      $this->FrenchTranslation->create(); 
      if ($this->FrenchTranslation->save($this->data)) { 
       $this->Session->setFlash(__('The french translation has been saved', true)); 
       $this->redirect(array('controller'=>'drugs','action' => 'index')); 
      } else { 
       $this->Session->setFlash(__('The french translation could not be saved. Please, try again.', true)); 
      } 
     } 
     $drugs = $this->FrenchTranslation->Drug->find('list'); 
     $this->set(compact('drugs')); 
    } 

    function edit($id = null) { 
    //$this->FrenchTranslation->id = $id; 
    $userid = $this->Auth->user('id'); 
    $username = $this->Auth->user('name'); 
    //$this->FrenchTranslation->user_id = $id; 
    $drug = $this->FrenchTranslation->Drug->read(
     array(
      'Drug.id','Drug.generic','Drug.ahl','Drug.aap','Drug.rid','Drug.oral','Drug.mw','Drug.clinical_recommendations', 
      'Drug.category','Drug.lrc' 
    ), 
     $id 
    ); 

    $this->set('drug',$drug); 
    $this->set('user',$userid); 
    $this->set('username',$username); 

     if (!$id && empty($this->data)) { 
      $this->Session->setFlash(__('Invalid french translation', true)); 
      $this->redirect(array('action' => 'index')); 
     } 
     if (!empty($this->data)) { 
      if ($this->FrenchTranslation->saveAll($this->data)) { 
       $this->Session->setFlash(__('The french translation has been saved', true)); 
       $this->redirect(array('controller'=>'drugs','action' => 'index')); 
      } else { 
       $this->Session->setFlash(__('The french translation could not be saved. Please, try again.', true)); 
      } 
     } 
     if (empty($this->data)) { 
      $this->data = $this->FrenchTranslation->read(null, $id); 
     } 
     $drugs = $this->FrenchTranslation->Drug->find('list'); 
     $this->set(compact('drugs')); 
    } 

    function delete($id = null) { 
     if (!$id) { 
      $this->Session->setFlash(__('Invalid id for french translation', true)); 
      $this->redirect(array('action'=>'index')); 
     } 
     if ($this->FrenchTranslation->delete($id)) { 
      $this->Session->setFlash(__('French translation deleted', true)); 
      $this->redirect(array('action'=>'index')); 
     } 
     $this->Session->setFlash(__('French translation was not deleted', true)); 
     $this->redirect(array('action' => 'index')); 
    } 

编辑观点：

<?php echo $this->Form->input('User.last_edit',array('type'=>'hidden','value'=>$drug['Drug']['generic'])); ?>  
    <?php echo $this->Form->input('user_id', array('type'=>'hidden','value'=>$user)); ?> 

Answer 1

我想通了，不过，我觉得有这样做的更好的，更安全，方式。我正在使用安全组件，并且一个人必须登录才能查看任何网站，所以它可能足够安全。

我只是为用户标识添加了一个user.id输入，此时它可以找到合适的用户来存储last_edit。在控制器中，我有一个名为$ userid的变量，它使用$userid = $this->Auth->user('id');获取当前用户标识，并使用$ths->set('user',$userid);传递给视图。我在输入中为用户user_id字段使用了相同的用户标识值。

查看：

<?php echo $this->Form->input('User.id',array('type'=>'hidden','value'=>$user));//The user ID last edit will be stored in ?> 
<?php echo $this->Form->input('User.last_edit',array('type'=>'hidden','value'=>$drug['Drug']['generic']));//The drug edited last by the specified user ?> 

Answer 2

这是一个有点晚了答案，但你永远不应该使用视图，设置安全的变量，例如user_id。相反，你可以在你的控制器设置这些变量：

$this->request->data['User']['last_edit'] = $this->request->data['Drug']['generic'];