如何选择使用XSLT从CDATA显示哪些数据？

Question

我从描述标签下面的XML提取数据：

<rss xmlns:yweather="http://xml.weather.yahoo.com/ns/rss/1.0" xmlns:geo="http://www.w3.org/2003/01/geo/wgs84_pos#" version="2.0"> 
<channel> 
<title>Yahoo! Weather - Dubai, AE</title> 
<link> 
http://us.rd.yahoo.com/dailynews/rss/weather/Dubai__AE/*http://weather.yahoo.com/forecast/AEXX0004_f.html 
</link> 
<description>Yahoo! Weather for Dubai, AE</description> 
<language>en-us</language> 
<lastBuildDate>Mon, 04 Mar 2013 9:01 pm GST</lastBuildDate> 
<ttl>60</ttl> 
<yweather:location city="Dubai" region="" country="United Arab Emirates"/> 
<yweather:units temperature="F" distance="mi" pressure="in" speed="mph"/> 
<yweather:wind chill="75" direction="350" speed="6"/> 
<yweather:atmosphere humidity="69" visibility="6.21" pressure="29.97" rising="0"/> 
<yweather:astronomy sunrise="6:39 am" sunset="6:23 pm"/> 
<image> 
<title>Yahoo! Weather</title> 
<width>142</width> 
<height>18</height> 
<link>http://weather.yahoo.com</link> 
<url> 
http://l.yimg.com/a/i/brand/purplelogo//uh/us/news-wea.gif 
</url> 
</image> 
<item> 
<title>Conditions for Dubai, AE at 9:01 pm GST</title> 
<geo:lat>25.27</geo:lat> 
<geo:long>55.31</geo:long> 
<link> 
http://us.rd.yahoo.com/dailynews/rss/weather/Dubai__AE/*http://weather.yahoo.com/forecast/AEXX0004_f.html 
</link> 
<pubDate>Mon, 04 Mar 2013 9:01 pm GST</pubDate> 
<yweather:condition text="Fair" code="33" temp="75" date="Mon, 04 Mar 2013 9:01 pm GST"/> 
<description> 
<![CDATA[ 
<img src="http://l.yimg.com/a/i/us/we/52/33.gif"/><br /> <b>Current Conditions:</b><br /> Fair, 75 F<BR /> <BR /><b>Forecast:</b><BR /> Mon - Clear. High: 86 Low: 67<br /> Tue - Sunny. High: 89 Low: 68<br /> <br /> <a href="http://us.rd.yahoo.com/dailynews/rss/weather/Dubai__AE/*http://weather.yahoo.com/forecast/AEXX0004_f.html">Full Forecast at Yahoo! Weather</a><BR/><BR/> (provided by <a href="http://www.weather.com" >The Weather Channel</a>)<br/> 
]]> 
</description> 
<yweather:forecast day="Mon" date="4 Mar 2013" low="67" high="86" text="Clear" code="31"/> 
<yweather:forecast day="Tue" date="5 Mar 2013" low="68" high="89" text="Sunny" code="32"/> 
<guid isPermaLink="false">AEXX0004_2013_03_05_7_00_GST</guid> 
</item> 
</channel> 
</rss> 
<!-- 
api3.weather.ch1.yahoo.com Mon Mar 4 17:44:49 PST 2013 
--> 

使用此XSLT：

<xsl:template match="channel"> 
    <xsl:element name="div"> 
     <!-- This holds the image links--> 
     <xsl:attribute name="id"> 
      <xsl:text>weatherdiv</xsl:text> 
     </xsl:attribute> 
     <table> 
      <xsl:attribute name="class">wtab</xsl:attribute> 
      <xsl:apply-templates select="item" /> 
     </table> 
    </xsl:element> 
</xsl:template> 
<xsl:template match="item"> 
    <tr> 
     <td colspan="2" > 
      <xsl:attribute name="id"> 
       <xsl:text>titletd</xsl:text> 
      </xsl:attribute> 
      <xsl:value-of select="title" /> 
     </td> 
    </tr> 
    <tr> 
     <td colspan="2"> 
      <xsl:attribute name="id"> 
       <xsl:text>descriptiontd</xsl:text> 
      </xsl:attribute> 
      <xsl:value-of select="description" disable-output-escaping="yes" /> 
     </td> 
    </tr> 
    <!-- ... --> 
</xsl:template> 

这条线：

<xsl:value-of select="description" disable-output-escaping="yes" /> 

得到一切都在说明，如何能我阻止它得到这部分：

(provided by <a href="http://www.weather.com" >The Weather Channel</a>) 

Answer 1

可以使用substring-before()功能：

<xsl:value-of select="substring-before(description, '(provided')" disable-output-escaping="yes" />