如何从数据库中提取的json数据获取特定值？

您好，我有问题显示从数据库中提取的JSON数据的特定值，我只想显示产品名称上的输入文本如何做到这一点？我尝试过，但它说没有价值。如何从数据库中提取的json数据获取特定值？

这里是我的JSON代码： -

{"brcode":[{"id":"1","name":"Rolex Watch","description":"Rolex wrist watches","uom":"1000","brand":"1051","tax_id":"1","purchase_price":"5000","sale_price":"6000","barcode":"ROLEX5000","created_date":"2017-05-29 13:31:24","created_by":"1","updated_date":"2017-05-29 13:31:24","updated_by":"1","status":null},{"id":"3","name":"motorola X play","description":"Moto X play mobile phone","uom":"50","brand":"7845","tax_id":"1","purchase_price":"20000","sale_price":"25000","barcode":"MOTOXPLAY500","created_date":"2017-05-29 14:18:43","created_by":"0","updated_date":"2017-05-29 14:18:43","updated_by":"0","status":null},{"id":"4","name":" LG Smart LED TV","description":"Smart LED TV from LG","uom":"5","brand":"5420","tax_id":"1","purchase_price":"80000","sale_price":"100000","barcode":"LGSMART5012","created_date":"2017-05-29 15:39:35","created_by":"0","updated_date":"2017-05-29 15:39:35","updated_by":"0","status":null},{"id":"5","name":"Computer Intel","description":"Intel smart computer","uom":"1","brand":"1","tax_id":"1","purchase_price":"40000","sale_price":"50000","barcode":"INTELPC2123","created_date":"2017-05-29 17:59:31","created_by":"0","updated_date":"2017-05-29 17:59:31","updated_by":"0","status":null},{"id":"6","name":"DDR4 Ram","description":"Ram for computer","uom":"6","brand":"1","tax_id":"1","purchase_price":"4000","sale_price":"5000","barcode":"RAMDDR4","created_date":"2017-05-29 18:15:17","created_by":"0","updated_date":"2017-05-29 18:15:17","updated_by":"0","status":null}]}

这里是我的功能： -

function get_barcodes() { 


    $.ajax({ 
     url: 'http://localhost/retail/main/ajax_barcodes/', 
     type: 'POST', 
     datatype: 'json', 
     data: { 'barcode': $('#brcode option:selected').val() }, 
     success: function (data) { 
      // var brcodes = JSON.parse(data); 
      //console.log(brcodes);   
      //var brCodes = JSON.parse(data); 
      //var json = JSON.parse(data); 
      //console.log(brCodes.brcode); 
      //$("#product_items_opts").val(barcodes.brcode.name); 
      // console.log(json); 

      console.log(data); 

     } 
    }); 

    // $('#prdct_barcode[' + product_barcode_counter + ']').each(function(){ 
    //  $('#prdct_barcode[' + product_barcode_counter + ']').change(function(){ 



    //  }); 
    // }); 


}

请忽略我写只是为了检查值的评论部分。请告诉我如何从JSON数据显示产品名称？

来源

2017-05-31 Pranay Sute

是否想获取所有产品名称并将其显示在某个地方？ – JSONGagnon

是的，我也想显示选择菜单的选项中的所有条形码，我想追加所有的条形码选项。 –

试试这个

var jsonData = JSON.parse(data); 
for(var i=0; i<jsonData.brcode.length; i++) { 
    var product = jsonData.brcode[i]; 
    console.log(product.name); 
}

来源

2017-05-31 18:56:06

Heyy非常感谢Nikita它的作品:) .. !! –

下面是一个基本的通过JSON循环来获得产品的名称和条形码。这应该可以帮助你实现你想要做的事情。将这些代码放在您的控制台登录数据的成功功能中。

var jsonData = JSON.parse(data); 
for(var i = 0; i < jsonData.brcode.length; i++){ 
    console.log(jsonData.brcode[i].name); 
    console.log(jsonData.brcode[i].barcode); 
}

来源

2017-05-31 18:56:46 JSONGagnon

这不会在控制台中显示任何内容 –

尝试先使用JSON.parse解析数据。 – JSONGagnon

如何从数据库中提取的json数据获取特定值？

回答

相关问题