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我正在运行一个方法来包含选择查询,但编译语句不工作的断点跳过它声明它的行,当我把光标放在它上,它显示没有值,这是代码我使用:选择查询不工作SQLite
-(NSMutableArray *)GetAllPartsName
{
NSString *path = [self getDBPath];
// Open the database from the users filessytem
NSMutableArray *Parts=[[[NSMutableArray alloc]init]autorelease ];
if(sqlite3_open([path UTF8String], &database) == SQLITE_OK) {
// Setup the SQL Statement and compile it for faster access
NSString *sqlQuery = [NSString stringWithFormat:@"SELECT Parts_Name FROM Parts"];
NSLog(@"%@",sqlQuery);
const char *sqlStatement = [sqlQuery UTF8String];
//The break point skips the sqlite3_stmt.
sqlite3_stmt *compiledStatement;
//when i put the cursor over compiledStatement it shows no value
if(sqlite3_prepare_v2(database, sqlStatement, -1, &compiledStatement, NULL) == SQLITE_OK) {
// Loop through the results and add them to the feeds array
while(sqlite3_step(compiledStatement) == SQLITE_ROW) {
// Read the data from the result row
NSMutableDictionary *PositionDict=[[NSMutableDictionary alloc]init];
//setting the parts into dictionary
[PositionDict setObject:[NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement,0)] forKey:@"Parts_Name"];
[Parts addObject:PositionDict];
NSLog(@"%@",PositionDict);
[PositionDict release];
}
}
// Release the compiled statement from memory
sqlite3_finalize(compiledStatement);
}
sqlite3_close(database);
return Parts;
}