密码解密失败

Question

好日子，

我有一个剧本我创建，读取用户输入，并将其与保存在一个文本文件中的关键。即使字符串是相同的，请帮助我：

from Crypto.Cipher import AES 
from tkinter import * 
#create the window 
root = Tk() 

#modify root window 
root.title("Button Example") 
#root.geometry("500x500") 

app = Frame(root) 
key='Key is unique!!!' 
IV='This is an IV456' 
#password=b'\xa3Y\x00\xae\xad\xad\x1c\xc6Js\xa9\xf4\x0e\xf3\x0f\xe3' 


def encrypt(): 
    obj = AES.new(key, AES.MODE_CBC, IV) 
    messagein = inputbar.get() 
    inputbar.delete(0,END) 
    messlen = len(messagein) 
    if messlen < 16: 
     diff = 16-messlen 
     message = 'z'*diff + messagein 
    global ciphertext 
    ciphertext = obj.encrypt(message) 
    print(ciphertext) 
    del obj 
def check(): 
    encrypt() 
    passwordfunc() 
    if ciphertext == password: 
     print('Success!') 
    else: 
     print('Fail!') 

def passwordfunc(): 
    file=open("E536D.dat","r") 
    global password 
    password = file.readline() 
    file.close() 
    print(password) 

inputbar = Entry(root,font='TkDefaultFont 30') 
inputbar.pack() 

button1= Button(text='Encrpyt',command=lambda:encrypt()) 
button1.pack() 
button2 = Button(text='Compare',command=lambda:check()) 
button2.pack() 
button3 = Button(text='File',command=lambda:passwordfunc()) 
button3.pack() 

root.mainloop() 

我做了什么错了？行#password=b'\xa3Y\x00\xae\xad\xad\x1c\xc6Js\xa9\xf4\x0e\xf3\x0f\xe3'是它需要比较的关键，但它从文件比较中返回false，但在它自己内部工作。请帮帮我。我通过移动obj = AES.new(key, AES.MODE_CBC, IV)来加密和删除函数结尾处的不同密钥输出。但是，当我比较文件中的字符串和正确的输入python仍然说他们不一样。下面是我的意思的截图。

Answer 1

好的我修好了。问题是密文是字节，我的文件有它理解为一个字符串，所以我没了下文，并使用字节读取它以字节为单位，现在它的工作原理100％

from Crypto.Cipher import AES 
from tkinter import * 
#create the window 
root = Tk() 

#modify root window 
root.title("Button Example") 
#root.geometry("500x500") 

app = Frame(root) 
key='Key is unique!!!' 
IV='This is an IV456' 
#password=b'\xa3Y\x00\xae\xad\xad\x1c\xc6Js\xa9\xf4\x0e\xf3\x0f\xe3' 


def encrypt(): 
    obj = AES.new(key, AES.MODE_CBC, IV) 
    messagein = inputbar.get() 
    inputbar.delete(0,END) 
    messlen = len(messagein) 
    if messlen < 16: 
     diff = 16-messlen 
     message = 'z'*diff + messagein 
    global ciphertext 
    ciphertext = obj.encrypt(message) 
    del obj 

def passwordfunc(): 
    file=open("E536D.dat","rb") 
    global password 
    password = file.readline() 
    file.close() 

def check(): 
    encrypt() 
    passwordfunc() 
    print('ciphertext = ',ciphertext) 
    print(' password = ',password) 
    if ciphertext == password: 
     print('Success!') 
    else: 
     print('Fail!') 

def write(): 
    encrypt() 
    file=open("E536D.dat","wb") 
    file.write(ciphertext) 
    file.close() 


inputbar = Entry(root,font='TkDefaultFont 30') 
inputbar.pack() 

button1= Button(text='Encrpyt',command=lambda:encrypt()) 
button1.pack() 
button2 = Button(text='Compare',command=lambda:check()) 
button2.pack() 
button3 = Button(text='File',command=lambda:passwordfunc()) 
button3.pack() 
button4 = Button(text='Write',command=lambda:write()) 
button4.pack() 

root.mainloop() 

由于其写入文件PM 2RIng为您的帮助。你的问题让我想到了，所以我设法用快速的谷歌修复它。非常感谢