如何分离这样的字符串？

Question

我得到含串联在一起，就像

def_ghi @ hotmail.com_abc_1 @ me.com

每个邮件是由underscore.The问题分开是不同的邮件一个NSString如果我试图分开字符串使用下划线字符，它也可以将单个电子邮件地址细分为下划线字符也可以在单个电子邮件中。我已经试过给了我这样的结果

高清

ghi@hotmail.com

ABC

1@me.com

这里是我的代码

NSString *string = //The string I am receiving. 
NSArray *chunks = [string componentsSeparatedByString: @"_"]; 

请帮帮我。

编辑： 我问一个资深的，他告诉我，我应该先搜索字符串“@” character.When我发现这一点，那么我寻找一个“_”，如果它存在更换。作为“@”之后的第一个下划线是分隔符。我应该从这个位置开始，然后重复上一步。我这样做直到字符串结束。请有人帮我解决这个问题。

Answer 1

解决方案使用正则表达式尝试，

NSString *yourString = @"def_ghi@hotmail.com_abc_1@me.com"; 
NSError *error = NULL; 
NSRegularExpression *regex = [NSRegularExpression 
           regularExpressionWithPattern:@"[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,4}" 
           options:NSRegularExpressionCaseInsensitive 
           error:&error]; 
[regex enumerateMatchesInString:yourString options:0 range:NSMakeRange(0, [yourString length]) usingBlock:^(NSTextCheckingResult *match, NSMatchingFlags flags, BOOL *stop){ 

    // detect email addresses 
    NSString *email = [yourString substringWithRange:match.range]; 

    //this part remove the '_' between email addresses 
    if(match.range.location != 0){ 
     if([email characterAtIndex:0]=='_'){ 
      email = [email substringFromIndex:1]; 
     } 
    } 

    //print the email address 
    NSLog(@"%@",email); 

}]; 

---

编辑：如何收集它们，

声明这样的变量，

@property(nonatomic, strong) NSMutableArray *emailsArray; 



_emailsArray = [[NSMutableArray alloc] init]; 

NSString *yourString = @"def_ghi@hotmail.com_abc_1@me.com"; 
NSError *error = NULL; 
NSRegularExpression *regex = [NSRegularExpression 
           regularExpressionWithPattern:@"[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,4}" 
           options:NSRegularExpressionCaseInsensitive 
           error:&error]; 
[regex enumerateMatchesInString:yourString options:0 range:NSMakeRange(0, [yourString length]) usingBlock:^(NSTextCheckingResult *match, NSMatchingFlags flags, BOOL *stop){ 

    // detect email addresses 
    NSString *email = [yourString substringWithRange:match.range]; 

    //this part remove the '_' between email addresses 
    if(match.range.location != 0){ 
     if([email characterAtIndex:0]=='_'){ 
      email = [email substringFromIndex:1]; 
     } 
    } 

    //print the email address 
    NSLog(@"%@",email); 
    [self.emailsArray addObject:email]; 
}]; 


NSLog(@"%@",self.emailsArray); 

然后只

Answer 2

NSString *string = @"def_ghi@hotmail.com_abc_1@me.com"; 
NSArray *stringComponents = [string componentsSeparatedByString:@"_"]; 

NSMutableString *mutableString = [NSMutableString string]; 
NSMutableArray *emailIDs = [NSMutableArray array]; 
for (NSString *component in stringComponents) { 
    if (!mutableString) { 
     mutableString = [NSMutableString string]; 
    } 
    [mutableString appendFormat:@"_%@",component]; 

    if ([component rangeOfString:@"@"].location != NSNotFound) { 
     [emailIDs addObject:[mutableString substringFromIndex:1]]; 
     mutableString = nil; 
    } 
} 

NSLog(@"%@",emailIDs); 

Answer 3

鉴于您的要求这样的事情应该为你工作：

NSString *string = @"def_ghi@hotmail.com_abc_1@me.com"; 
NSMutableArray *addresses = [NSMutableArray array]; 
NSUInteger currentIndex = 0; // start from beginning 
// Stop when we are past the end of the string 
while (currentIndex < string.length) { 
    // Find the next @ symbol 
    NSRange atRange = [string rangeOfString:@"@" options:0 range:NSMakeRange(currentIndex, string.length - currentIndex)]; 
    if (atRange.location != NSNotFound) { 
     // We found another @, not look for the first underscore after the @ 
     NSRange underRange = [string rangeOfString:@"_" options:0 range:NSMakeRange(atRange.location, string.length - atRange.location)]; 
     if (underRange.location != NSNotFound) { 
      // We found an underscore after the @, extract the email address 
      NSString *address = [string substringWithRange:NSMakeRange(currentIndex, underRange.location - currentIndex)]; 
      [addresses addObject:address]; 
      currentIndex = underRange.location + 1; 
     } else { 
      // No underscore so this must be the last address in the string 
      NSString *address = [string substringFromIndex:currentIndex]; 
      [addresses addObject:address]; 
      currentIndex = string.length; 
     } 
    } else { 
     // no more @ symbols 
     currentIndex = string.length; 
    } 
} 

NSLog(@"Addresses: %@", addresses); 

Answer 4

这里就如何重新构建从你发现自己与有些凌乱的字符串的邮件地址的原始名单有很多很好的答案。

我想提出一个NSScanner基础的解决方案，这似乎是非常适合：

NSString *messyString = @"def_ghi@hotmail.com_abc_1@me.com"; 

NSScanner *mailScanner = [NSScanner scannerWithString:messyString]; 

NSMutableArray *mailAddresses = [NSMutableArray array]; 

while (YES) { 

    NSString *recipientName; 
    NSString *serverName; 
    BOOL found = [mailScanner scanUpToString:@"@" intoString:&recipientName]; 
    found |= [mailScanner scanUpToString:@"_" intoString:&serverName]; 
    if (!found) break; 

    [mailAddresses addObject:[recipientName stringByAppendingString:serverName]]; 

    // Consume the delimiting underscore 
    found = [mailScanner scanString:@"_" intoString:nil]; 
    if (!found) break; 
}