的WordPress：含有表格和自定义表的查询自定义模板

Question

的WordPress 4.4.2主题=从WPZoom

我已经创建了一个包含狗的自定义表的SQL查询自定义模板Meeta。查询通过WPDB类正常工作，我可以以可接受的格式显示输出数据。

现在在相同的自定义模板中，我插入一个php表单以允许用户输入搜索条件。

表单显示正常，但查询立即执行而无需等待用户点击提交，因此我无法输入任何搜索条件。我应该怎么做才能保留查询，直到表单被提交？

，如果我介绍主页错误在其他地方显示返回而不显示错误，我已经摆弄周围了一段时间，很多次。我是否必须打开错误显示或将它发送到某处的日志中。

 <?php the_content(); ?> 
       //================================= 
       <?php 

       function test_input($data) { 
       $data = trim($data); 
       $data = stripslashes($data); 
       $data = htmlspecialchars($data); 
       return $data; 
       } 

       // set variables to wildcard 
       $dog_name = "%"; 
       ?> 

       <h2>Chercher dans la base</h2> 
       <form method="post" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>"> 

       Dog_name: <input type="text" dog_name="dog_name" value="<?php echo $dog_name;?>"> 

       <input type="submit" name="submit" value="Submit"> 

       </form> 

       <?php 
       $dog_name = test_input($_POST["dog_name"]); 

       global $wpdb; 

       $query = "SELECT offspring.dog_name, offspring.sex, offspring.color, offspring.dob, offspring.cotation, offspring.titles, offspring.hd, offspring.titles, offspring.eyes, offspring.dna, offspring.born_in, offspring.prod_prop, sire.dog_name AS sire, dam.dog_name AS lice 
        FROM BP_dog AS offspring 
        JOIN BP_dog AS sire ON sire.dog_id = offspring.sire_id 
        JOIN BP_dog AS dam ON dam.dog_id = offspring.dam_id 
        ORDER BY dog_name"; 
       word      
        $results = $wpdb->get_results($query); 

        $num_rows = $wpdb->num_rows; 
        print "Number of rows = $num_rows.<br>"; 

        foreach ($wpdb->get_results($query)as $row) { 
        print $row->dog_name . "\t"; 
        print $row->sex . "\t"; 
        print $row->dob . "\t"; 
        print $row->color . "\t"; 
        print $row->cotation . "\t"; 
        print $row->titles . "\t"; 
        print $row->hd . "\t"; 
        print $row->eyes . "\t"; 
        print $row->dna . "\t"; 
        print $row->born_in . "<br>"; 
        print "Sire = " . $row->sire . "\t"; 
        print "Lice = " . $row->lice . "<br>"; 
        print $row->prod_prop . "<br><br>"; 
        } 
        ?> 

Answer 1

如果页面加载/重载，您写的查询将直接运行。使用isset执行代码只ID您$_POST数据。

<h2>Chercher dans la base</h2> 
<form method="post" action="http://localhost/wordpress/?page_id=4"> 
Dog_name: <input type="text" name="dog_name" value="<?php echo $dog_name;?>"> 
<input type="submit" name="submit" value="Submit"> 
</form> 
<?php 
if (isset($_POST["dog_name"])) { 
function test_input($data) { 
$data = trim($data); 
$data = stripslashes($data); 
$data = htmlspecialchars($data); 
return $data; 
} 
$dog_name = test_input($_POST["dog_name"]); 

global $wpdb; 

$query = "SELECT offspring.dog_name, offspring.sex, offspring.color, offspring.dob, offspring.cotation, offspring.titles, offspring.hd, offspring.titles, offspring.eyes, offspring.dna, offspring.born_in, offspring.prod_prop, sire.dog_name AS sire, dam.dog_name AS lice 
    FROM BP_dog AS offspring 
    JOIN BP_dog AS sire ON sire.dog_id = offspring.sire_id 
    JOIN BP_dog AS dam ON dam.dog_id = offspring.dam_id 
    ORDER BY dog_name"; 

    $results = $wpdb->get_results($query); 

    $num_rows = $wpdb->num_rows; 
    foreach ($wpdb->get_results($query)as $row) { 
    print $row->dog_name . "\t"; 
    print $row->sex . "\t"; 
    print $row->dob . "\t"; 
    print $row->color . "\t"; 
    print $row->cotation . "\t"; 
    print $row->titles . "\t"; 
    print $row->hd . "\t"; 
    print $row->eyes . "\t"; 
    print $row->dna . "\t"; 
    print $row->born_in . "<br>"; 
    print "Sire = " . $row->sire . "\t"; 
    print "Lice = " . $row->lice . "<br>"; 
    print $row->prod_prop . "<br><br>"; 
    } 
} 
?> 

我还修改了几件事情上的代码：

1. 删除 “word” 在第46行

2. 变化input type="text" dog_name="dog_name"到input type="text" name="dog_name"

3. 删除$dog_name = "%";。不知道为什么你正在使用这个