如何从一个变量

Question

继How to get folder path from file path with CMD

我想从一个变量剥离路径（不包含文件名）获得路径。遵循上面讨论的方法的逻辑，我想使用批量波纹管，这不起作用。任何接受者？可能？

set cpp="C:\temp\lib.dll" 
echo %cpp% 
"C:\temp\lib.dll" 
echo %~dpcpp 
"C:\temp\" > doesn't work 

Answer 1

测试：demo.bat

@echo off 
echo "Setting cpp" 
set cpp="C:\temp\lib.dll" 

echo "Calling JustGetPath" 
call :JustGetPath %cpp% 

echo "Returning result" 
echo %_RESULT% 

echo "Quitting" 
goto :eof 

:JustGetPath 
echo " +JustGetPath(%1)" 
set _RESULT=%~dp1 

echo " -JustGetPath()" 
GOTO :eof 

:eof 

输出以下运行时：

"Setting cpp" 
"Calling JustGetPath" 
" +JustGetPath(C:\temp\lib.dll)" 
" -JustGetPath()" 
"Returning result" 
C:\temp\ 
"Quitting" 

参见：http://ss64.com/nt/call.html

Answer 2

可以使用for命令，就像这样：

set cpp="C:\temp\lib.dll" 

:: Print the full path and file name: 
echo %cpp% 

:: Print just the path: 
for %%P in (%cpp%) do echo %%~dpP