如何获得LAMBDA在LINQ实际筛选动态LINQ

例子，我有一个个人类如何获得LAMBDA在LINQ实际筛选动态LINQ

Public Class Person 
Private _fname As String 
Public Property Fname() As String 
    Get 
     Return _fname 
    End Get 
    Set(ByVal value As String) 
     _fname = value 
    End Set 
End Property 
Private _lname As String 
Public Property Lname() As String 
    Get 
     Return _lname 
    End Get 
    Set(ByVal value As String) 
     _lname = value 
    End Set 
End Property 
Private _age As Integer 
Public Property Age() As Integer 
    Get 
     Return _age 
    End Get 
    Set(ByVal value As Integer) 
     _age = value 
    End Set 
End Property

末级

Dim people As New List(Of Person) 
    people.Add(New Person With {.Fname = "Alice", .Lname = "Apples", .Age = 1}) 
    people.Add(New Person With {.Fname = "Bob", .Lname = "Banana", .Age = 2}) 
    people.Add(New Person With {.Fname = "Charlie", .Lname = "Cherry", .Age = 3}) 
    people.Add(New Person With {.Fname = "Dave", .Lname = "Durian", .Age = 4}) 
    people.Add(New Person With {.Fname = "Eric", .Lname = "EggPlant", .Age = 10}) 

    Dim filteredPerson = From person In people 
    filteredPerson.Where(Function(fp) fp.Fname = "Bob") 

    Dim finalList = filteredPerson.ToList 
    For Each p In finalList 
     Debug.Print("FNAME: " + p.Fname) 
    Next

这仍然返回所有5人，喜欢在那里不被应用，我做错了什么？

我也想能够通过名称列表，并只返回

Dim searchList As New List(Of String) 
    searchList.Add("Bob") 
    searchList.Add("Dave") 

    Dim filteredPerson = From person In people 
    For Each s In searchList 
     Dim innerName As String = s 
     filteredPerson.Where(Function(fp) fp.Fname = innerName) 
    Next 
    Dim finalList = filteredPerson.ToList 
    For Each p In finalList 
     Debug.Print("FNAME: " + p.Fname) 
    Next

来源

2009-09-10 Eric

的问题是，如果不变化集合。它返回新过滤的集合。

试试这个：

Dim filteredPerson = people.Where(Function(fp) fp.Fname = "Bob")

（顺便说一句，我没有你在哪里使用动态LINQ看到任何动态这里......？）

要添加多个Where子句， “会想是这样的：

Dim searchList As New List(Of String) 
searchList.Add("Bob") 
searchList.Add("Dave") 

Dim filteredPerson As IEnumerable(Of String) = people 
For Each s In searchList 
    Dim innerName As String = s 
    filteredPerson = filteredPerson.Where(Function(fp) fp.Fname = innerName) 
Next 
Dim finalList = filteredPerson.ToList 
For Each p In finalList 
    Debug.Print("FNAME: " + p.Fname) 
Next

不过，我不相信这是实际上你想要做什么。每个Where条款将坚持Fname是指定的名称 - 它不会是鲍勃和戴夫！我想你真正想要的东西可以更简单地表示：

Dim searchList As New List(Of String) 
searchList.Add("Bob") 
searchList.Add("Dave") 

Dim filteredPerson = people.Where(Function(fp) searchList.Contains(fp.Fname)) 
Dim finalList = filteredPerson.ToList 
For Each p In finalList 
    Debug.Print("FNAME: " + p.Fname) 
Next

所有我们想知道的是Fname是否searchList，这是什么呢Contains。

来源

2009-09-10 16:47:39

它是在最后的代码段中，我希望能够传递名称列表，添加每个名称的where子句，在该示例中，我期望列出（Person）列表中的2个项目Bob ＆Dave – Eric 2009-09-10 16:51:53

就是这样！这正是我想传达的。谢谢 – Eric 2009-09-10 16:55:22

@Jon：我不知道语法。你可以用JOIN来举例说明第二种情况吗？ – shahkalpesh 2009-09-10 16:55:31

Dim people As New List(Of Person) 
people.Add(New Person With {.Fname = "Alice", .Lname = "Apples", .Age = 1}) 
people.Add(New Person With {.Fname = "Bob", .Lname = "Banana", .Age = 2}) 
people.Add(New Person With {.Fname = "Charlie", .Lname = "Cherry", .Age = 3}) 
people.Add(New Person With {.Fname = "Dave", .Lname = "Durian", .Age = 4}) 
people.Add(New Person With {.Fname = "Eric", .Lname = "EggPlant", .Age = 10}) 

Dim searchList As New List(Of String) 
searchList.Add("Bob") 
searchList.Add("Dave") 

dim filteredItems = from p in people _ 
join i in searchList on p.FName equals i _ 
select p 

dim personFound as Person 

for each personFound in filteredItems 
    Console.WriteLine(personFound.Lname) 
next

来源

2009-09-10 17:28:08 shahkalpesh

如何获得LAMBDA在LINQ实际筛选动态LINQ

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