PHP - 基于值的合并2多维数组

Question

目前，我有2个多维数组，我正在寻找将它们组合成一个巨型数组，其中数组1中的值名称与数组2中的值名称匹配。 数组的外观作为跟随...

Array1 
(
    [0] => Array 
     (
      [id] => 1 
      [name] => test1 
      [desc] => test_desc 
      [quantity] => 3 
     ) 

    [1] => Array 
     (
      [id] => 2 
      [name] => test2 
      [desc] => test_desc 
      [quantity] => 33 
     ) 

) 


Array2 
(
    [0] => Array 
     (
      [holder] => 'John' 
      [name] => test1 
      [desc] => test_desc 
      [location] => ATL 
     ) 

    [1] => Array 
     (
      [holder] => 'Jackie' 
      [name] => test3 
      [desc] => test_desc 
      [location] => SF 
     ) 

) 

我正在寻找合并其中阵列1的“名称”列数组2相匹配的阵列以及在阵列的1 & 2相结合的列到最后一个数组。这看起来像...

FinalArray 
(
    [0] => Array 
     (
      [id] => 1 
      [holder] => 'John' 
      [name] => test1 
      [desc] => test_desc 
      [location] => ATL 
      [quantity] => 3 
     ) 

    [1] => Array 
     (
      [holder] => 'Jackie' 
      [name] => test3 
      [desc] => test_desc 
      [location] => SF 
     ) 

    [2] => Array 
     (
      [id] => 2 
      [name] => test2 
      [desc] => test_desc 
      [quantity] => 33 
     ) 

) 

凡“测试1”融合了跨2个阵列的不同列到里面的“FinalArray”一个新的数组。我试着用array_merge和array_merge_recursive来研究一些想法，但我不完全确定我是否会朝着正确的方向前进。提前致谢。

Answer 1

尝试这样

$array1=[['id' => 1,'name' => 'test1','desc' => 'test_desc','quantity' => 3], 
    ['id' => 2,'name' => 'test2','desc' => 'test_desc','quantity' => 33]]; 
$array2=[['holder' => 'John','name' => 'test1','desc' => 'test_desc','location' => 'ATL'], 
    ['holder' => 'Jackie','name' => 'test3','desc' => 'test_desc','location' => 'SF']]; 
$final=[]; 
foreach ($array1 as $key1=>$data1){ 
    foreach ($array2 as $key2=>$data2){ 
     if($data1['name']==$data2['name']){ 
      $final[]=$data1+$data2; 
      unset($array1[$key1]); 
      unset($array2[$key2]); 
     } 
    } 
} 
if(!empty($array1)){ 
    foreach ($array1 as $value){ 
     $final[]=$value; 
    } 
} 
if(!empty($array2)){ 
    foreach ($array2 as $value){ 
     $final[]=$value; 
    } 
} 

它会给输出

Answer 2

还有一个解决方案

function merge_by_name(array $arr1, array $arr2) { 
    $result = []; 

    foreach ($arr1 as $value) { 

     $key = array_search($value['name'], array_column($arr2, 'name')); 

     if($key !== false) { 
      $result[] = array_merge($value, $arr2[$key]); 
      unset($arr2[$key]); 
     } else { 
      $result[] = $value; 
     } 
    } 
    $result = array_merge($result, $arr2); 

    return $result; 
} 

---

测试

$arr1 = [ 
    [ 
     'id' => 1, 
     'name' => 'test1', 
     'desc' => 'test_desc', 
     'quantity' => 3 
    ], 
    [ 
     'id' => 2, 
     'name' => 'test2', 
     'desc' => 'test_desc', 
     'quantity' => 33 
    ], 
]; 

$arr2 = [ 
    [ 
     'holder' => 'John', 
     'name' => 'test1', 
     'desc' => 'test_desc', 
     'location' => 'ATL' 
    ], 
    [ 
     'holder' => 'Jackie', 
     'name' => 'test3', 
     'desc' => 'test_desc', 
     'location' => 'SF' 
    ], 
]; 

var_export(merge_by_name($arr1, $arr2)); 

结果

array (
    0 => 
    array (
    'id' => 1, 
    'name' => 'test1', 
    'desc' => 'test_desc', 
    'quantity' => 3, 
    'holder' => 'John', 
    'location' => 'ATL', 
), 
    1 => 
    array (
    'id' => 2, 
    'name' => 'test2', 
    'desc' => 'test_desc', 
    'quantity' => 33, 
), 
    2 => 
    array (
    'holder' => 'Jackie', 
    'name' => 'test3', 
    'desc' => 'test_desc', 
    'location' => 'SF', 
), 
)