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我有一个实现IntentService的类,它从Web服务中检索一些数据,并且如果条件已验证,则在通知栏的设备上显示通知。 这是代码:意向服务,选择要启动的活动
现在,如果在通知用户水龙头,闪屏活动启动(我的应用程序的它的第一个活动)public BackgroundService() {
super("SERVICENAME");
}
@Override
protected void onHandleIntent(Intent intent) {
if (verifyConditions()) {
showNotification();
}
}
private void showNotification() {
NotificationCompat.Builder builder = new NotificationCompat.Builder(
this).setContentTitle("title")
.setContentText("content")
.setSmallIcon(R.drawable.notification_icon);
// .setContentIntent(pendingIntent);
Intent notificationIntent = new Intent(this.getApplicationContext(),
SplashScreen.class);
PendingIntent contentIntent = PendingIntent.getActivity(
this.getApplicationContext(), 0, notificationIntent, 0);
notificationIntent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP
| Intent.FLAG_ACTIVITY_SINGLE_TOP);
// set sound
Uri alarmSound = RingtoneManager
.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
builder.setSound(alarmSound);
builder.setContentIntent(contentIntent);
Notification notification = builder.build();
// Hide the notification after it's selected
notification.flags |= Notification.FLAG_AUTO_CANCEL;
NotificationManager notificationManager = (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);
notificationManager.notify(0, notification);
}
。如果用户关闭了应用程序,这是可以的,但如果应用程序在前台,点击通知会导致应用程序重新启动。 有一个快速的方法来检查应用程序是否在前台,如果是的话,启动一个不同的活动,以SplashScreen?
plaese阅读“Intent.FLAG_ACTIVITY_CLEAR_TOP”的文档 – Selvin 2015-04-02 10:19:31