我有一个基于ViewModel的表单,它提示用户将Person的XApplication
状态更改为Accepted或Rejected。HttpGet和HttpPost返回验证错误并加载SelectList
当我通过POST提交表单时,我想创建一个新的XApplication
,然后如果成功将用户带回同一页面。如果它包含错误,我希望再次通过传递View(personApp)
重新载入表单,这将通过剃刀方法@Html.ValidationSummary()
显示错误。
但是,当我尝试这样做时,View()不知道我的SelectLists,并且无法使用“应用程序已接受”和“应用程序已拒绝”填充下拉列表。
我可以采取另一种方法吗?
[Route("student/xApplication/{personId?}")]
[HttpGet]
public ActionResult xApplication(int? personId)
{
if (personId == null)
{
return new HttpStatusCodeResult(HttpStatusCode.BadRequest);
}
Person person = db.People.Find(personId);
if (person == null)
{
return HttpNotFound();
}
// Prepare ViewModel to pass to view, based on personId
PersonViewModel personVModel = new PersonViewModel();
personVModel.Person = person;
// Get XApplication Data
var xApps = from a in db.XApplications where a.personId == personId select a;
XApplication personXApplication = null;
if (xApps.Count() > 0)
{
personXApplication = xApps.First();
}
personVModel.XApplications = personXApplication;
List<SelectListItem> applicationStatusItems = new List<SelectListItem>();
applicationStatusItems.Add(new SelectListItem { Value = "1", Text = "Application Accepted" });
applicationStatusItems.Add(new SelectListItem { Value = "0", Text = "Application Rejected" });
SelectList applicationStatusList = new SelectList(applicationStatusItems, "Value", "Text", null);
personVModel.ApplicationStatusList = applicationStatusList;
return View(personVModel);
}
[HttpPost]
[Route("student/xApplication")]
public ActionResult xApplication(PersonViewModel personVModel)
{
if (ModelState.IsValid)// Checks no errors
{
db.XApplications.Add(personVModel.XApplications);
db.SaveChanges();
return Redirect("/student/xApplication/" + personVModel.Person.id);
}
return View(personVModel);
}
你可以做的是让视图模型自己照顾selectlistitem。因此,您不必重新填充控制器中的项目。 – Jamie 2014-09-26 14:50:36
我会给那一个去杰米,是有道理的。 – 2014-09-26 15:07:14