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我使用ASIHTTP到POST数据到服务器,并在接收到所有的数据,因为它应该ASIHTTP上传白色图像
我上传与
[request1 setData:imageData withFileName:@"upload.png" andContentType:@"image/png" forKey:@"Image"];
图像这里的imageData是NSData的
-(void)imagePickerController:(UIImagePickerController *)picker didFinishPickingMediaWithInfo:(NSDictionary *)info
{
NSString *mediaType = [info objectForKey:UIImagePickerControllerMediaType];
[self dismissModalViewControllerAnimated:YES];
if ([mediaType isEqualToString:(NSString *)kUTTypeImage]) {
UIImage *image = [info objectForKey:@"UIImagePickerControllerOriginalImage"] ;
UIGraphicsBeginImageContext(CGSizeMake(320,480));
UIImage *newImage = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();
CGSize kMaxImageViewSize = {.width = 100, .height = 100};
//[self resizeImage:newImage newSize:kMaxImageViewSize];
imageData=UIImageJPEGRepresentation([self resizeImage:newImage newSize:kMaxImageViewSize], 0.5);
}
- (UIImage *)resizeImage:(UIImage*)image newSize:(CGSize)newSize {
CGRect newRect = CGRectIntegral(CGRectMake(0, 0, newSize.width, newSize.height));
CGImageRef imageRef = image.CGImage;
UIGraphicsBeginImageContextWithOptions(newSize, NO, 0);
CGContextRef context = UIGraphicsGetCurrentContext();
// Set the quality level to use when rescaling
CGContextSetInterpolationQuality(context, kCGInterpolationHigh);
CGAffineTransform flipVertical = CGAffineTransformMake(1, 0, 0, -1, 0, newSize.height);
CGContextConcatCTM(context, flipVertical);
// Draw into the context; this scales the image
CGContextDrawImage(context, newRect, imageRef);
// Get the resized image from the context and a UIImage
CGImageRef newImageRef = CGBitmapContextCreateImage(context);
UIImage *newImage = [UIImage imageWithCGImage:newImageRef];
CGImageRelease(newImageRef);
UIGraphicsEndImageContext();
return newImage;
}
这是我如何重新调整图像的大小。我的问题是,当图像被保存在服务器上时,我只是得到一个白色的图像,空白的一个。它是一个服务器的问题,或者也可以是我不发送表单应用程序
编辑 这里是我的服务器代码
$filename="upload";
$target_path = "uploads/";
$target_path = $target_path .$filename.".png";
if(move_uploaded_file($_FILES['file']['tmp_name'], $target_path)) {
echo "uploaded an image";
} else{
echo "There was an error uploading the file, please try again!";
}
我做这种方式为我工作。谢谢 – SALMAN 2012-07-09 21:02:37
没有帮助。从我可以看到的方式来看,这可能是服务器(php)问题 – Spire 2012-07-11 02:47:15
@Spire是的!如果它仍然无法正常工作,那么webservice端必须存在问题?你有php的代码结束了吗?我可以为你解决这个问题。谢谢 – SALMAN 2012-07-11 07:37:51