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Question

请如何写这个简单的工作选择，在Hibernate查询，或标准

SELECT * FROM `call` AS c JOIN `event_customer` AS e ON c.customer_id = e.customer_id WHERE e.dgdelete = FALSE AND c.eventruletype_id = 1 AND e.event_id = 74 AND c.callactivity_id = 3 AND e.calltype = 2 

我发现已经有很多建议，但没有任何帮助我呢。

它可能是什么与Hibernate映射？

谢谢。

PS： 这是行不通的

query = session.createQuery("select c from " + Call.class.getSimpleName()+ " as c " + EventCustomer.class.getSimpleName()+ " as e where e.customer_id = c.customer_id and e.event_id = 74"); 

也是这个工作不

query = session.createQuery("select c from " + Call.class.getSimpleName()+ " as c join " + EventCustomer.class.getSimpleName()+ " as e where e.customer_id = c.customer_id and e.event_id = 74"); 

而且这个

query = session.createQuery("select c from " + Call.class.getSimpleName()+ " as c join " + EventCustomer.class.getSimpleName()+ " as e on e.customer_id = c.customer_id where e.event_id = 74"); 

而且这个

query = session.createQuery("select c from " + Call.class.getSimpleName()+ " as c left join " + EventCustomer.class.getSimpleName()+ " as e on e.customer_id = c.customer_id where e.event_id = 74"); 

，并在某些情况下，我得到这个错误

Answer 1

这应该工作。 （用逗号替换JOIN）

Query query = session.createQuery("select c from " + Call.class.getSimpleName() + " as c , " + EventCustomer.class.getSimpleName() + " as e where e.customer.id = c.customer.id and c.event.id = 74"); 

Answer 2

不要连击，而使用标准：

Criteria crit = session.createCriteria(Call.class, "c") 
    .createCriteria("eventCustomerDto","e") 
    .add(Restrictions.eq("event_id",74)); 
List<Call> list=crit.list(); 

的代码可能有错别字，但多数民众赞成这个想法。另外，对于我的例子，我认为Call和EventCustomer之间的Call Hibernate映射存在一对多关系。