我想要在用户仪表板上自动显示这些结果,当用户登录到他们的仪表板时,我希望此查询运行并向他们显示其用户ID的统计信息。请建议如何做到这一点。如何获得登录用户ID,统计的工作代码在下面发布。获取登录从codeigniter会话中的用户ID
echo '<pre>'; print_r($this->session->all_userdata());exit;
我越来越:
<?php
$query = $this->db->query("SELECT
tblclients.userid as client_id,
tblclients.company as company_name,
IFNULL(tblinvoices.total, 0) AS total_amount,
IFNULL(tblinvoicepaymentrecords.amount, 0) AS paid_amount,
(IFNULL(tblinvoices.total, 0) - IFNULL(tblinvoicepaymentrecords.amount, 0)) AS amount_due
FROM
tblclients
LEFT JOIN tblinvoices ON tblclients.userid = tblinvoices.clientid
LEFT JOIN tblinvoicepaymentrecords ON tblinvoices.id = tblinvoicepaymentrecords.invoiceid
WHERE tblclients.userid = 1");
foreach ($query->result_array() as $row)
{
echo $row['total_amount'] . " " . $row['paid_amount'] . " " .$row['amount_due'];
echo "<br />";
}
?>
检查这个代码后
Array
(
[__ci_last_regenerate] => 1504507372
[client_user_id] => 1
[contact_user_id] => 1
[client_logged_in] => 1
[red_url] => https://www.trisuka.com/crm/admin
)
任何人,请帮帮忙。 –
如何获得用户登录? ?您必须将它存储在codeigniter会话中? ? –
@Root Ingenious:谢谢你在这里,好友,是的,我已经存储了,但正如你可以看到上面的代码,一个是由你给出的完整的sqlquery,我将如何在选择语句中应用用户ID,现在它是手动userid = 1 ..或者我必须从数据库中获取所有的用户ID和结果,将不得不筛选使用会话。 –