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我已经创建了一些动画和过渡的径向结帐进度条。在按钮上添加了事件。但问题是我在结帐的每一步都有不同的内容。最佳做法是什么?是否更好地使用数据attr。为了这。内容应隐藏并显示特定结帐。 codepen结帐辐射进度条事件
<div class="step-1" id="checkout-progress" data-current-step="1">
<div class="progress-bar">
<div class="step step-1 active " data-step="1"><span> 1</span>
<div class="step-check">t</div>
<div class="step-label"> address</div>
</div>
<div class="step step-2" data-step="2"><span> 2</span>
<div class="step-check">a</div>
<div class="step-label"> shipping</div>
</div>
<div class="step step-3" data-step="3"><span> 3</span>
<div class="step-check">b</div>
<div class="step-label"> payment</div>
</div>
<div class="step step-4" data-step="4"><span> 4</span>
<div class="step-check">3</div>
<div class="step-label"> summary</div>
</div>
</div>
</div>
<!-- <div class="button-container">
<div class="btn btn-prev"> previous step</div>
<div class="btn btn-next"> next step</div>
</div> -->
<div class="checkout-content" data-step="1">
<h1>checkout content 1</h1>
<div class="btn btn-next"> next step</div>
<div class="btn btn-next"> next step</div>
</div>
<div class="checkout-content" data-step="2">
<h1>checkout content 2</h1>
<div class="btn btn-next"> next step</div>
<div class="btn btn-next"> next step</div>
</div>
<div class="checkout-content" data-step="3">
<h1>checkout content 3</h1>
<div class="btn btn-next"> next step</div>
<div class="btn btn-next"> next step</div>
</div>
<div class="checkout-content" data-step="4">
<h1>checkout content 4</h1>
<div class="btn btn-next"> next step</div>
<div class="btn btn-next"> next step</div>
</div>
$('.btn-next').on('click', function() {
var currentStepNum = $('#checkout-progress').data('current-step');
var nextStepNum = (currentStepNum + 1);
var currentStep = $('.step.step-' + currentStepNum);
var nextStep = $('.step.step-' + nextStepNum);
var progressBar = $('#checkout-progress');
$('.btn-prev').removeClass('disabled');
if(currentStepNum == 5) {
return false;
}
if(nextStepNum == 5){
$(this).addClass('disabled');
}
// $('.checkout-progress').removeClass('.step-' + currentStepNum).addClass('.step-' + (currentStepNum + 1));
currentStep.removeClass('active').addClass('valid');
currentStep.find('span').addClass('opaque');
currentStep.find('.step-check').removeClass('opaque');
nextStep.addClass('active');
progressBar.removeAttr('class').addClass('step-' + nextStepNum).data('current-step', nextStepNum);
});
$('.btn-prev').on('click', function() {
var currentStepNum = $('#checkout-progress').data('current-step');
var prevStepNum = (currentStepNum - 1);
var currentStep = $('.step.step-' + currentStepNum);
var prevStep = $('.step.step-' + prevStepNum);
var progressBar = $('#checkout-progress');
$('.btn-next').removeClass('disabled');
if(currentStepNum == 1) {
return false;
}
if(prevStepNum == 1){
$(this).addClass('disabled');
}
// $('.checkout-progress').removeClass('.step-' + currentStepNum).addClass('.step-' + (prevStepNum));
currentStep.removeClass('active');
prevStep.find('span').removeClass('opaque');
prevStep.find('.step-check').addClass('opaque');
prevStep.addClass('active').removeClass('valid');
progressBar.removeAttr('class').addClass('step-' + prevStepNum).data('current-step', prevStepNum);
});
我使用不同的元素来通过所有结帐,包含部分中的所有下一个按钮应该是。 –
为此,我更新了我的答案,请检查 –
我将为您创建Codepen等待... –