在一个节点中存储一个完整的数组

Question

我试图在一个节点中存储一个int数组。我没有按照我应该的方式获得节点。任何人可以提供的帮助都会很棒。

public void readIn() 
    { 
    int counter = 1; 
    try { 
     Scanner inFile = new Scanner(new FileReader("WordProblemData.txt")); 
     int times = Integer.parseInt(inFile.next()); 
     for (int a = 1;a <= times; a++) 
     { 
      for (int i = 1; i <= 8; i++) 
      { 
       num[i-1] = Integer.parseInt(inFile.next()); 
       System.out.println(num[i-1]); 

      } 
      data = (String)(inFile.next()); 
      System.out.println(data); 



      head = new DateStampNode(data,num,head); 
     } 
     inFile.close(); 

Answer 1

除非你有一个大的预分配数组，否则我相信你需要在填充它之前分配一个新数组。您可能还想记得增加num。

Answer 2

我不知道你的问题还真是（应该您在您看来会得到什么？），但它可能是这样的：

int[] num = new int[8]; //you should allocate a new array, otherwise you'd overwrite the values in the next iteration of the outer loop 
for (int i = 1; i <= 8; i++) 
{ 
    num[i-1] = Integer.parseInt(inFile.next()); 
    System.out.println(num[i-1]); 
} 
data = (String)(inFile.next()); 
System.out.println(data); 

//you're storing num here, so you'd need a new num array for the next iteration, see above 
head = new DateStampNode(data,num,head);