如何从两个表格中进行选择？

Question

我有表 '文章'

 
+-------------+ 
| articles | 
+----+--------+ 
| id | title | 
+----+--------+ 
| 1 | title1 | 
+----+--------+ 
| 2 | title2 | 
+----+--------+ 
| 3 | title3 | 
+----+--------+ 

表 '目录'

 
+---------------------+ 
|  catalogue  | 
+----+--------+-------+ 
| id | group | name | 
+----+--------+-------+ 
| 1 | group1 | name1 | 
+----+--------+-------+ 
| 2 | group1 | name2 | 
+----+--------+-------+ 
| 3 | group2 | name3 | 
+----+--------+-------+ 
| 4 | group2 | name4 | 
+----+--------+-------+ 

绑定表 'bindTable'

 
+------------+--------------+-------+ 
|    bindTable   | 
+------------+--------------+-------+ 
| id_article | id_catalogue | value | 
+------------+--------------+-------+ 
|  1  |  2  | 1 | 
+------------+--------------+-------+ 
|  1  |  3  | 4 | 
+------------+--------------+-------+ 
|  3  |  1  | 2 | 
+------------+--------------+-------+ 
|  3  |  3  | 1 | 
+------------+--------------+-------+ 
|  3  |  4  | 3 | 
+------------+--------------+-------+ 

和我需要得到结果如表 '结果' ，在那里我可以得到配对“catalogue_name：价值”从表'文章'的选定项目

 
+-----------------------------------------------------+ 
|      result      | 
+------------+---------------+----------------+-------+ 
| article_id | article_title | catalogue_name | value | 
+------------+---------------+----------------+-------+ 
|  1  |  title1 | group1_name2, | 1 | 
|   |    | group2_name3 | 4 | 
+------------+---------------+----------------+-------+ 
|  3  |  title3 | group1_name1, | 2 | 
|   |    | group2_name3, | 1 | 
|   |    | group2_name4 | 3 | 
+------------+---------------+----------------+-------+ 

任何人都可以告诉我一个查询字符串与一个数据库查询？感谢您的关注。

 
My vision: 
    SELECT b.id_article, a.title, c.group, c.name, b.value 
    FROM bindTable b 
    JOIN articles a ON a.id = b.id_articles 
    JOIN catalogue c ON c.id = b.id_catalogue 
    WHERE b.id_article = 1 

，但我需要一个一行对c.name & b.value一个a.id

Answer 1

一个选择与内部联接

select a.article_id, a.article_title, b.catalogue_name, b.value 
from bindTable as c 
inner join articles as a on a.id = c. article_id 
inner join catalogues as b on c. id_catalogue = b.id 

Answer 2

这应该这样做。

SELECT articles.id AS article_id, 
     articles.title AS article_title, 
     CONCAT_WS('_', catalogue.group, catalogue.name) AS catalogue_name, 
     bindTable.value AS value 
FROM bindTable 
    INNER JOIN articles ON bindTable.id_article = articles.id 
    INNER JOIN catalogue ON bindTable.id_catalogue = catalogue.id