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此函数接受字符串作为参数,然后对数字进行加密并应将加密字符串写入文件。在主要的eText似乎没有得到任何东西从功能,我不明白为什么。加密函数不会输出字符串,因为它应该是
功能定义:
string Encipherer::encipherer(string plainMessage){
int i = plainMessage.length();
string eMessage;
cout << i << endl;
for(i = 0; i >= plainMessage.length(); i++){
if(plainMessage[i] >= 65 && plainMessage[i] <= 90){
if(plainMessage[i] + shift > 90){
eMessage[i] += plainMessage[i] - 26 + shift;
}
else{
eMessage += plainMessage[i] + shift;
}
}
else if(plainMessage[i] >= 97 && plainMessage[i] <= 122){
if(plainMessage[i] + shift > 122){
eMessage[i] += plainMessage[i] - 26 + shift;
}
else{
eMessage += plainMessage[i] + shift;
}
}
}
else{
eMessage += plainMessage[i];
}
}
return eMessage;
}
主要功能:
int main(){
string plainMessage, eText;
string fileName = "inputText.txt";
ofstream outputText;
outputText.open ("outputText.txt");
Encipherer E(5);
plainMessage = E.encipherFromFile(fileName);
eText = E.encipherer(plainMessage);
outputText << eText;
outputText.close();
return 0;
}
提前感谢!
谢谢Tomcaa。它现在工作! – aegon52 2013-02-13 00:08:02